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Prompt
Complete the following Python function: ```python def sort_even(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the odd indicies, while its values at the even indicies are equal to the values of the even indicies of l, but sorted. >>> sort_even([1, 2, 3]) [1, 2, 3] >>> sort_even([5, 6, 3, 4]) [3, 6, 5, 4] """ ```
Answer guidance
Canonical solution (function body): evens = l[::2] odds = l[1::2] evens.sort() ans = [] for e, o in zip(evens, odds): ans.extend([e, o]) if len(evens) > len(odds): ans.append(evens[-1]) return ans
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