Now I need to generate a FIBA basketball court in SVG with regulation dimensions. This needs to be self-contained HTML since the user might render it in an iframe/browsers. The user asked "Genérame una cancha de baloncesto FIBA (con las medidas perfectas reglamentarias) en SVG y sus correspondientes líneas." in Spanish. Respond in Spanish. Provide a code block containing full HTML with SVG. Need correct FIBA dimensions. Need to ensure all styles and SVG included. Could include a script? Maybe not necessary. They ask for SVG and lines. Use regulation FIBA court dimensions: total playing area 28 m x 15 m, inner court lines 5cm width. Three-point line: radius 6.75 m from basket center, with straight lines 0.90 m? Actually FIBA three-point line: minimum distance from sidelines maybe 0.90 m? Need accurate. FIBA court measurements (post-2010): - Court length 28 m, width 15 m. - Center circle radius 1.80 m. - Free throw lane/key: rectangle 4.90 m wide by 5.80 m long (restricted area = key), inner lines. Actually lane space marks: free-throw line 3.60 m length, 5.80 m from baseline to free-throw line. The restricted area (key) width 4.90 m (distance between lane lines), length 5.80 m. There are semicircle free-throw circle? Free throw circle radius 1.80 m centered at midpoint of free throw line. - No-charge semicircles (restricted area arcs) radius 1.25 m from centers of baskets. - Three-point line radius 6.75 m from basket center, with parallel lines 0.90 m from each sideline? Actually the three-point line begins as straight lines parallel to sidelines at distance of 0.90 m from sideline? Need verify: For FIBA, the three-point line is a semicircle of radius 6.75 m from the basket center. The straight parts are 0.90 m from the inner edge of each sideline and parallel to the sidelines, extending from the baseline? Let's recall exact geometry. From anywhere within playing court, the three-point field goal area includes the semicircle and the parallel lines. The parallel lines are perpendicular? Hmm. FIBA 2014 rules define three-point field goal line: radius of 6.75 m measured from the point on the floor beneath the centre of the basket. The straight lines are drawn parallel to the sidelines for a distance of 0.90 m from the inner edge of sidelines? Wait. Actually NBA: three-point line is arc radius from basket, with straight lines at 3 ft from sidelines. FIBA: The three-point line is demarcated by a semicircle of radius 6.75 m from the center of the basket. The two parallel lines are perpendicular to the endlines and touch the arc. Let me search memory: For FIBA three-point line, the straight lines are 0.90 m from each sideline, parallel to the side-lines, and are 1.575 m long? Not sure. Let's derive: FIBA court width 15 m. Basket center is 1.575 m from baseline (or 1.60? The official distance from endline to center of basket is 1.575 m; backboard protrudes 1.20 m from baseline, and basket center is 0.375 m from front plane, so total 1.575 m). The arc radius 6.75 m. The arc would cross the sideline at some distance from baseline. The straight lines begin where the arc meets lines parallel to sideline? Actually to form a closed area, the three-point line has straight portions from baseline to where they meet the arc, but these straight portions are not necessarily along the baseline/sideline. In many diagrams, the three-point line includes two straight lines parallel to the sidelines at x = (15/2 - 0.90)? Wait coordinate system: half court width 7.5, basket at x=7.5 y=1.575? If arc centered at basket, points (x,y) satisfying (x-7.5)^2 + (y-1.575)^2 = 6.75^2. At the sideline y? Actually sideline x=0 or x=15. Then distance from basket center to sideline at same end baseline is sqrt((7.5)^2 + (1.575)^2) = 7.68 > 6.75. So the arc does not reach sideline. Therefore the three-point line has straight segments from the baseline to the arc, near the corners. These straight segments are parallel to the sideline? If they are at x = 0.90 or x=14.10, then endpoints are on the arc. Let's verify: if a vertical line x = 0.90 (distance 0.90 from left sideline x=0), intersection with arc above baseline: (0.90 - 7.5)^2 + (y - 1.575)^2 = 6.75^2 => (-6.6)^2 = 43.56. 6.75^2 = 45.5625. Remainder = 2.0025. sqrt = 1.415. y = 1.575 + 1.415 = 2.99 m from baseline. The straight line from baseline y=0 to y=2.99 at x=0.90. That seems plausible? Common FIBA three-point straight line length is 2.70 m? Maybe with distance from baseline to first point ~2.70. Actually maybe the straight distance from baseline is around 3.02 m if radius 6.75 and 0.75? Let's examine FIBA diagram. FIBA rules: "The three-point line is parallel to and 0.90 m from the side-lines." I recall wording: "The three-point line is the radius of 6.75 m from the point on the floor vertically below the center of the opponents' basket. The parallel lines are perpendicular to the end lines and 0.90 m from and parallel to the side-lines." Maybe the lines are 0.90 m from the sideline; yes. Alternative: "The parallel lines are perpendicular to the side-lines." Wait. Let's recall exact from FIBA Official Basketball Rules 2018: "Art. 2.4.3 Three-point field goal area. The three-point field goal area shall be the entire floor area of the playing court, with the exception of the area near the opponents' basket, limited by and including the parallel lines and the arc as follows: (a) The parallel lines shall be marked perpendicular to the endlines, at a distance of 0.90 m from the inner edge of the sidelines. The distance shall be measured from the inner edge of the sideline to the inner edge of the three-point line." Hmm. I will produce a diagram with the standard accepted dimensions, and note dimensions. Since this is an HTML page, maybe embed scaling. Need full HTML with SVG court. We'll produce a well-commented SVG. We need to ensure aspect ratio and viewBox. Use coordinate system in meters: court 28x15. Add margin. Use line strokes 0.05m appropriate. We should use vector-effect non-scaling? Just use viewBox and set stroke widths in user units (meters) to approx 0.05 m. Need labels maybe. Or display dimensions. Provide maybe some styling for interactivity? But user asked only SVG. Need to render in iframe possible. Ensure code block with full HTML. We can write in Spanish and include code. Let's construct accurately. Coordinate system: Let x horizontal from left sideline (0 to 15). Let y vertical from bottom baseline to top opposite baseline (0 to 28). Baskets at Y=1.575 and Y=26.425 (since 28 - 1.575). X center = 7.5. Court: outer boundary rectangle x=0..15, y=0..28 (the inside edge of lines is the court; line width 0.05 extends outside? For SVG, draw center of boundary at 0 and 15? Better draw inner rectangle lines half-width inside; but visually fine. Add a surrounding area). Lines: - Court boundary: rectangle. - Center line: horizontal at y=14 from x=0 to x=15. - Center circle: radius 1.80, center (7.5,14). - Center line and circle line width. - Free-throw lanes at each end: rectangle from baseline to 5.80 m into court, centered horizontally, width 4.90. So lane lines x=7.5 ±2.45; y from 0 to 5.80 at bottom; and from 28 to 22.20 at top. - Free-throw line: line x=7.5 ±1.80? Actually free-throw line length 3.60 connecting lane lines at y=5.80 (bottom) and y=22.20 (top). The line width included. - Free-throw circle: radius 1.80 m centered at basket center? Actually center at midpoint of free-throw line (7.5, 5.80) and (7.5, 22.20). The free throw semicircle is drawn with dashed line inside lane? The free-throw circle is radius 1.80 m; the part inside the lane is dashed, part outside solid? Actually FIBA: the free-throw circle is drawn with a solid line and the part inside the restricted area (key) should be drawn as a dashed line. Wait: FIBA key includes free-throw circle portion inside key? Let's clarify: In FIBA, the free throw semicircle is marked with a solid line outside the key and a dashed line inside the key. The free-throw circle is centered at the midpoint of the free throw line (7.5,5.8). Radius 1.8. It intersects the free-throw line; the area inside the lane between the free-throw line and the basket? Actually the key is the restricted area bounded by endline, lane lines, and free-throw line. The free throw circle extends into the key from the free-throw line towards the basket for 1.8 m, but the key length is 5.8 m from baseline to free-throw line. The free-throw circle center at y=5.8, radius 1.8, so inside key goes from y=4.0 to y=5.8. But the basket is at y=1.575, so it doesn't reach basket. Why is there a circle around free-throw line? It defines positions for players: the area inside the lane is marked with dashed line to indicate free-throw circle inside restricted area. So yes: full circle of radius 1.80, dashed inside the lane (between y=0 and y=5.8? Actually inside lane rectangle). The segment of the circle within the key (y between 0 and 5.8) should be dashed, outside should be solid. But is the circle drawn only as semicircle? FIBA diagram shows free-throw circle with dashed line inside restricted area and solid line outside, meeting at the free-throw line. We can implement as a full circle with different stroke? SVG allows path with mixed dash? Could draw dashed arc inside key and solid arc outside. - Restricted area (no-charge semicircle) under basket: radius 1.25 m from basket center, drawn as semicircle from baseline with center at basket. Wait FIBA no-charge semicircle: "A semi-circle shall be marked on the playing court with the radius of 1.25 m from the point on the floor beneath the exact centre of the opponent's basket. The semi-circle is marked with a solid line. It ends at the endline." Actually it's from baseline, a semicircle inside the court with center on the baseline? Let me recall: In FIBA, the no-charge semicircle has its center at the point on the floor directly below the center of the basket and its radius is 1.25 m. It is drawn inside the playing court with the line ends on the endline. The basket center is 1.575 m from endline. A radius of 1.25 m from basket center; the semicircle away from basket extends to y=1.575+1.25=2.825. It intersects the baseline at y=0? Solve: x^2 + (0-1.575)^2 = 1.25^2 -> 2.481 > 1.562, no intersection. Wait that seems center is not on baseline. Then the no-charge semicircle doesn't touch baseline if centered at basket. But FIBA diagram shows a semicircle in the key from baseline around the basket, maybe centered at point on endline? Let's verify. Maybe the center for no-charge semicircle is on the endline, directly below the basket? Actually basket center is 1.575 m from endline. If center at intersection of endline and basket vertical plane? But the basket is away from endline. The restricted area: "The restricted area shall be the rectangular area marked by the endline and the lines which are 2.45 m from the centre of the basket." No, that's key. No-charge semicircle in FIBA: There is a semi-circle marked in the key area with a radius of 1.25 m from the point on the floor beneath the center of the basket, and the ends of the line are on the endline? If center is basket center (1.575m from baseline), radius 1.25m, plus maybe because line is drawn from baseline to the semicircle, using baseline segment? Hmm maybe I recall incorrectly; let's examine. FIBA rule "No-charge semi-circle areas": The no-charge semi-circle areas shall be marked on the playing court. They are marked by: - A semi-circle with the radius of 1.25 m measured from the point on the floor beneath the exact centre of the basket to the inner edge of the semi-circle. The semi-circle is joined to: - Two parallel lines perpendicular to the endline, 0.375 m in length and ending 1.20 m from the inner edge of the endline. Actually that's the no-charge semicircle? Wait the lines 0.375 m are hash marks? The no-charge semicircle is similar to NBA restricted area arc but with radius 1.25 m. Its center is directly below basket center. It extends into the court; it intersects the baseline? Since center is 1.575 m from baseline, radius 1.25 m less than 1.575, it does not reach baseline. So you need lines from endpoints to baseline (perpendicular to baseline, length 0.375 m?) Perhaps: endpoints of the arc are at distance from baseline? Let me compute endpoints of the semicircle directed into court: the semicircle is on the side toward the court, so endpoints are where the circle meets a line? Actually the full circle centered at basket has points. The no-charge semicircle area is a half-disk on court side of a line parallel to baseline through basket? The baseline side is farther. Wait the basket is 1.575m from baseline, so a radius of 1.25m centered at basket reaches a maximum toward baseline at y=0.325m and maximum away at y=2.825m. The semicircle facing the court (away from baseline) would have endpoints somewhere with y coordinate less than baseline? No endpoints of a semicircle cut by a vertical line through center? Let's define center (7.5,1.575). A half circle with diameter maybe along a line parallel to baseline at y=1.575? Then endpoints are (7.5±1.25,1.575) and arc toward increasing y. That's a semicircle not touching baseline, with flat edge (diameter) under basket. But FIBA no-charge semicircle areas include lines along endline? I need exact. Maybe for FIBA, no-charge semicircle center is on the endline, radius 1.25m, so it extends from baseline to y=1.25 and reaches baseline endpoints. But basket center is 1.575m from baseline, so not matching. Hmm. Wait maybe I confuse the FIBA no-charge semicircle radius and center. Let's search memory: The FIBA no-charge semicircle area was introduced to match NBA restricted area. The area is defined by the semicircle underneath the basket with radius 1.25m, measured from the point on the floor beneath the centre of the basket. The lines of the semicircle end on the endline, and there are maybe no extra lines. But as geometry, a semicircle of radius 1.25 m centered below basket (1.575 from endline) is wholly inside the court and does not touch the endline. However the area described for no-charge is the semicircle with a 0.325m gap to baseline; but rule says "The no-charge semi-circle line is part of the no-charge semi-circle area." Hmm. Maybe the center is at the point on the floor beneath the front of the rim? Actually point on floor vertically below the centre of the basket is correct. Radius 1.25 m. The semicircle is marked from the points where the circle intersects lines parallel to sidelines? Wait if you draw a semicircle toward the court, its endpoints are 1.25m left and right of basket center at same y=1.575. Then from these endpoints, lines extend to the endline? Maybe but let's not overcomplicate. We can include a 1.25m radius arc around basket inside the court connected to baseline by vertical lines at endpoints? Many diagrams show no-charge semicircle as a half-circle attached to the endline. Actually perhaps the center is on the endline, not basket. Let's check: The distance from endline to the basket center in FIBA is 1.60 m or 1.575? The no-charge semicircle radius is 1.25 m, which is less than 1.60. If centered on baseline, area extends to y=1.25, not reaching basket. That wouldn't cover the key. In NBA, restricted area arc is radius 4 ft from basket center, and it is drawn as a semicircle in the lane, not touching baseline. The basket in NBA is 4 ft from baseline? Actually NBA basket center is 4'11"? Let's recall: NBA basket center is 5'3" (1.575?) Actually NBA backboard is 4 ft from baseline, rim center is 5.25 ft from baseline? Wait NBA: baseline to backboard 4 ft (1.219 m); rim center is 6 inches behind front plane of backboard (0.152 m), so basket center is 4.5 ft (1.3716 m) from baseline. Restricted area radius 4 ft (1.219 m), so center basket, arc ends at baseline? Circle centered 4.5 ft from baseline radius 4 ft: endpoints at x±4 ft, y=0.5 ft from baseline, so not touching. Still a gap. The restricted area includes the area within the semicircle plus lines? Actually NBA restricted area is the area within the arc and from the arc to the baseline? The arc is inside the lane. Because basket center is 4.5 ft from baseline > 4 ft radius, so the arc is in the lane; the restricted area itself is bounded below by the baseline and the arc connects to baseline with invisible vertical lines? Actually if you take the semicircle cut by line through center parallel to baseline (y=4.5), the half toward court has endpoints at y=4.5, not baseline. So not touching. Maybe the restricted arc is the half of the circle facing the baseline? That would extend into area behind basket (out of bounds). Not right. Let's settle by using widely accepted FIBA diagrams for court. I know most FIBA court SVGs use: - Court 28x15. - No-charge semicircles radius 1.25m centered at basket centers; semicircle drawn with solid line maybe ending at baseline? Actually many diagrams show a semicircle from baseline with radius 1.25 m centered at the point on floor beneath basket center, but because center is 1.575m from baseline, the semicircle opens toward the court and ends near baseline? Let's derive the two intersection points of the full circle with the baseline y=0: x = 7.5 ± sqrt(1.25^2 - 1.575^2) = imaginary. If radius were 1.6+, real. So no intersection with baseline. Thus it cannot end on baseline if radius 1.25. Unless the no-charge semicircle is the half of the circle toward the baseline (near basket), but then it extends out of bounds behind basket, with endpoints at a line through center parallel to baseline. But area is inside the court? The no-charge area excludes under basket? Actually the no-charge area is around basket, includes directly under basket; it is a semi-circle with radius 1.25m around basket center, located below the basket (i.e., between basket and baseline) with the straight side toward the court? Wait no-charge is area where charge cannot be drawn under the basket. It is the half circle between basket and baseline (closer to endline). If basket center 1.575m from endline, a radius of 1.25m toward baseline will reach at y=0.325m within court, not out of bounds. The semicircle is on the side of the baseline relative to the basket, its diameter being vertical? No. Let's define semicircle cut by line through basket center perpendicular to baseline (i.e., the line y=1.575). The half facing the baseline goes from y=0.325 to y=1.575, with endpoints at y=1.575, x=7.5±1.25. That is a half circle inside the court near baseline. Then the straight edge is a segment at y=1.575, from x=6.25 to 8.75. This is plausible: the no-charge semicircle is under the basket, opening to the court? Actually its flat side (along a line parallel to baseline through basket) faces the court, and arc faces baseline. This area lies within 1.25m directly below the basket. It resembles NBA restricted area arc but smaller and shifted because center is 1.575m from baseline, radius 1.25m, so the arc is between basket and baseline. In NBA restricted area, basket center distance 4.5ft and radius 4ft, similarly arc is between basket and baseline. Yes that's correct! The restricted area is a half-circle with its diameter along a line through the basket center parallel to baseline, and the curved part towards the baseline. Wait NBA restricted area: drawn as an arc in the lane with the basket at top? Let's recall TV view: Under the basket there is a dashed half-circle (restricted area), with its arc opening toward the free throw line, not baseline. Actually on TV, you see the restricted area arc as a semicircle under the hoop, with straight line (diameter) attached to the baseline? It opens toward the court (free-throw line). Hmm which side? In NBA, the restricted area is a half-circle with radius 4 ft from the basket (hoop). It extends from the baseline out; the arc is farthest from the baseline, and the straight line is along the baseline? Many diagrams: The restricted area is the area within the four-foot radius arc, measured from the basket, which extends to the baseline (i.e., a semicircle with its straight edge on the baseline). But because basket is 4.5ft from baseline, the radius 4ft doesn't reach baseline; however they include two lines from arc endpoints perpendicular to baseline? Actually official NBA restricted area: it is the area bounded by the baseline and a half-circle with a radius of 4 feet from the center of the basket. Wait, apparently center of basket is 4.75 ft from baseline? Let's check exact NBA: Distance from backboard to baseline = 4 ft. Hoop center is 6 inches from front of rim to plane, so from baseline to hoop center = 4.5 ft. If restricted area radius = 4 ft from center, a half-circle with diameter on a line through center perpendicular to baseline won't reach baseline. But official definition: "restricted area shall be the area on the playing court bounded by the free-throw lane lines, the free-throw line, and the half circle with a radius of 4 feet from the exact center of the basket." Wait no, maybe it is a semicircle inside the key, with diameter along free-throw lane line? Let's check memory: In NBA, the restricted area arc is a half-circle with radius 4 ft drawn from center of basket. It doesn't connect to baseline; it just sits in paint, with the straight side maybe along a line ... Actually watch NBA court: under basket near free throw line, there is a small dashed semicircle (the restricted area) that is in the lower part of the key, opening upward toward free-throw line. Its endpoints appear to be at distance from baseline maybe a bit less than a foot? No, the baseline is top of key? Wait orientation: Baseline at top or bottom. In typical half-court diagrams, baseline at bottom. Key extends upward. Restricted area arc is near bottom of key, with arc bowing toward baseline, and its ends attach to? The arc's endpoints are on two lines? The restricted area is the half-circle between the basket and baseline, with the straight edge (diameter) passing through the basket center (parallel to baseline). Yes: it defines area directly under hoop. The arc opens toward baseline; its diameter is a line through basket center. So my earlier semicircle facing baseline is the restricted area. It doesn't touch baseline. Good. Thus for FIBA no-charge semicircle: radius 1.25 m from basket center, semicircle facing the baseline (i.e., toward endline), with diameter along line y = basket y (parallel to baseline). That means arc composed of points distance 1.25 from basket and y <= basket y. It lies between y = basket_y - 1.25 and y = basket_y. Since basket_y = 1.575, baseline y=0, arc reaches y=0.325. Good. Some diagrams maybe use solid line for this. We'll draw solid. Also there are "hash marks"/lines for no-charge zone? FIBA no-charge semicircle line has maybe joins to baseline with lines? Need not. Correct hash marks: In FIBA, along the lane lines, there are positions for players: three spaces each side. Lane space markings: lines 10 cm long perpendicular to lane line, at distances? They are lines perpendicular to the lane line, with first at baseline? Actually FIBA lane spaces: The lane spaces along the neutral zone are marked along the free-throw lane lines. They are 0.85 m long (maybe parallel to baseline) and 0.10 m wide. The first one at 1.75 m from baseline, next at 2.70 m, next at 3.60 m, and next at 4.45 m? For FIBA: There are 6 spaces, 3 each side. Let's verify. FIBA key marks (in official rules): The lane spaces for players during free throws are marked as follows: - First space: 1.75 m from the baseline; length along lane line 0.85 m. - Second space: 1.60 m from first? Actually second space 3.35 m from baseline? Wait. Maybe let's recall from a known FIBA courtDim list: - key width: 4.90, length: 5.80. - Free throw line: 3.60 long at 5.80 from baseline. - Lane spaces: lines 10 cm x 85 cm marked along lane lines at 1.75 m, 2.70 m, 3.60 m, and 4.45 m from baseline (on each side)? That gives 4 lines? But there are only 3 spaces per side. Let's examine. Height of free throw circle inside key? The free-throw circle radius 1.8, ends at y=5.8-1.8=4.0 and y=5.8+1.8=7.6. Lane length 5.8. The spaces: - Top space (near free-throw line): between 4.70 and 5.80? Actually need four lines to define 3 spaces. FIBA marks the lane spaces using 85 cm marks perpendicular to lane line, and the distances between them: The first space is 1.75 m from baseline, the second is 1.60 m from first, the third is 1.25 m from second. The first space 0.85m long; second 0.85m; third 0.85m; remaining to free throw line is 1.25? Let's compute: 1.75 + 0.85 + 0.10 (gap?) + ... Not sure. Actually let's derive from known rule: The neutral zone/restricted area spaces are marked along each lane line. The first lane space mark nearest the baseline is 1.75 m from the baseline. Each lane space is 0.85 m long. There is a 0.10 m gap? Let's search memory: "The lane space marks are 0.10 m wide and 0.85 m long. They shall be marked outside the restricted area on both sides. The first mark is 1.75 m from the endline, the second mark 2.70 m from the endline, and the third mark 3.60 m from the endline; then the free-throw line is at 5.80 m." That would have 3 marks, not spaces, because line length 0.85 extends outward. Distance between first and second 0.95m, second to third 0.90m. Then from third to free-throw line 2.20m. That seems long. FIBA free throw lane: From Official Rules diagram annotation: - Lane line length 5.80m. - Position 1 (nearest baseline): 1.75m from endline, length of space = 0.85. - Position 2: 1.60m from position 1, length =0.85. - Position 3: 1.25m from position 2, length =0.85. - From position 3 to free-throw line: 1.20m? Let's sum: 1.75 + 1.60 + 1.25 = 4.60; plus 0.85? Wait positions are start points or centers? Maybe positions are distances to centers of spaces. Alternative known dimensions from FIBA/Euroleague floor: marking lines along the key called "zona neutra" at distances: 1.75 m, 3.35 m, 4.60 m, 5.80 m. Actually those are starts of spaces: first 0.85 long (ends 2.60), gap 0.75 (starts 3.35)?? Let's not guess. Better perhaps include lane space marks at commonly accepted positions: from baseline at 1.75 m, 2.70 m, 3.60 m, and 4.45 m. Many online FIBA courts show 4 marks per side; but the free throw lane has 4 marks? Let's check image memory: On a FIBA key, there are small tick marks on each side of lane (for player positions): near the baseline, there are two marks close together (defensive positions), and then a larger gap, and near free-throw line maybe one mark. Actually there are 4 marks per side because there are designated spots: 2 defensive along the lane, 2 offensive? Wait free-throws: max 6 players can line up: 2 along each lane line, plus the shooter and possibly 2 behind 3-point line. Actually 4 players line up in marked spaces, 2 on each side. But FIBA lane spaces: There are 8 spaces? Let's recall: During free throws, along each lane line there are three spaces/marked positions? Actually rule: "The lane spaces are marked for players; they are 0.85m long and 0.10m wide." There are 6 spaces (3 on each lane line)? But only 4 non-shooters can line up along lane; but maybe the first space is reserved, leaving three? Hmm. From FIBA 2022 rules, diagram: Lane space marks distances from end line: marks at 1.75 m, 3.35 m, 4.60 m. Or maybe each lane line shows three marks? Let's check: positions measured to nearest edge of the mark: 1.75m, 2.70m, 3.60m? I'm uncertain. But for SVG we can include a reasonable representation and maybe skip precise lane space marks to avoid errors. The main required lines: boundaries, center line, center circle, three-point line, free throw lane, free throw line, free throw circle, restricted area arcs. The lane space tick marks are secondary but part of FIBA court. If uncertain, omit or use accepted positions from common diagram. The request: "Genérame una cancha de baloncesto FIBA (con las medidas perfectas reglamentarias) en SVG y sus correspondientes líneas." Means generate FIBA basketball court with regulation measurements in SVG and corresponding lines. We can include all standard lines. It's okay if lane spaces are slightly off unless we state exact. Better we use an accurate reliable source. Let's research from memory / search mental. FIBA court official dimensions (in metres): - Playing court: 28 x 15 - Lines: 5 cm width - Center circle: 1.80 radius - Thrown-in areas at sidelines maybe between center line and each endline? Actually no. Three-point line: - Radius 6.75 m from basket center. - Parallel lines 0.90 m from inner edge of sidelines, perpendicular to baseline? length to arc. - The distance between the inner edges of the parallel lines and the inner edge of the sideline is 0.90m. Restricted area/no-charge semicircle: - Radius 1.25 m from basket center. - Straight line (diameter) at line through basket center parallel to baseline? Actually typical FIBA court drawing: no-charge semicircle is a half circle under the basket, with the line ends on the endline? Hmm need to resolve. Let's look up memory of official FIBA rule Art. 2.4.7 No-charge semi-circle areas: "The no-charge semi-circle areas shall be marked on the playing court as follows: (a) A semi-circle with the radius of 1.25 m measured from the point on the floor beneath the exact centre of the opponent's basket to the inner edge of the semi-circle. The semi-circle is joined to ... (b) Two lines perpendicular to the endline, 0.375 m in length and ending 1.20 m from the inner edge of the endline. (c) The no-charge semi-circle lines are part of the no-charge semi-circle area." Wait maybe not. Actually the no-charge semi-circle is similar to a "restricted area" but with a small rectangle maybe. Let me recall: The no-charge semicircle line is a semi-circle with radius 1.25m, with its center at the point on the floor beneath the center of the basket, and the semi-circle line is drawn inside the court. The ends of the semi-circle line are on the endline? But geometry says no. Unless the center is not the basket center but a point 1.25m away? Let's compute: If center at basket y=1.575, the circle reaches baseline only if radius >=1.575. FIBA might have changed endline-to-basket distance in metric to 1.60, radius maybe 1.60? But regulation radius is 1.25. So not. So perhaps the line is indeed not touching baseline and the no-charge area includes a rectangle to baseline? Let's search memory of actual rule text. I think the no-charge semicircle area is the shaded area under the basket bounded by: - A semi-circle of radius 1.25 m, with center at the point on the floor under the basket, and - Two parallel lines perpendicular to the endline, of length 0.375 m, ending 1.20 m from the endline. Wait maybe these lines are the "T" lines for throw-in. Actually FIBA has "Team bench areas", "Throw-in areas" etc. Let's find more systematically. I can reason from geometry of no-charge semicircle: Area is a half-circle of radius 1.25 with center at basket. The half-circle is on the side towards the baseline. Then the straight edge is a 2.5m long line through the basket center, parallel to baseline. It does not touch baseline. The no-charge semicircle area thus is a half-disk inside the key. The rule says "The no-charge semi-circle areas are marked on the playing court. They are limited by and include the semi-circle line and two parallel lines." The two parallel lines presumably connect the ends of the semi-circle to the baseline, perpendicular to baseline. Their length: from y=basket_y - 1.25? Wait arc endpoints at (7.5±1.25, 1.575). If we draw perpendicular lines to baseline (vertical), they reach y=0 at x=7.5±1.25, length =1.575. But not 0.375. Alternatively if the no-charge area is on court side of basket (toward free-throw), arc endpoints at y=1.575, and then two parallel lines (perpendicular to endline) from endpoints to baseline? Length =1.575. No. Maybe I recall "The semi-circle is joined to two parallel lines perpendicular to the endline, 0.90 m in length..." Hmm. Let's not let this block. We can implement a no-charge semicircle as a half-circle radius 1.25 m centered at the basket center, opening towards the baseline, with the straight edge (diameter) at the basket center line. This is standard and matches many FIBA court vector graphics. Or opening toward the court? Which one is right? Need to ensure correctness. For FIBA, I believe the "no-charge semicircle" is a semicircle with radius 1.25 m, measured from the point on the floor beneath the center of the basket, and it is drawn in the area inside the key between the basket and the endline. That means the diameter is through the basket center parallel to the endline, with the arc towards the endline. Yes. It is "under the basket," meaning closer to baseline, not facing the free-throw line. The line may be solid. Thus in the bottom end, basket at y=1.575; arc below it (toward y=0) with endpoints at (6.25,1.575) and (8.75,1.575). At top end, basket at y=26.425; arc above it (toward y=28) endpoints (6.25,26.425) and (8.75,26.425). This area is under the hoop. That I think is correct. Free-throw circle: I think should be drawn with solid line outside lane and dashed inside lane. At bottom, center (7.5,5.8), radius 1.8. The part for y > 5.8 (toward center of court) is outside the key -> solid semicircle. The part for y < 5.8 (toward baseline, inside key) is dashed. At top, center (7.5,22.2), outside part y<22.2 (toward center) solid, inside y>22.2 dashed. Center circle: solid circle in the middle. Three-point line: Use path arc + straight lines. Need to define properly: For bottom basket center C=(7.5, 1.575), radius R=6.75. The three-point line consists of two straight segments parallel to sidelines at x = 7.5 - 6.6? Wait earlier I assumed 0.90 from sideline (x=0.90 and x=14.10). But the FIBA rule: "The parallel lines shall be drawn at right angles to the endline, at a distance of 0.90 m from the inner edge of the sidelines. These lines are 2.35 m long and meet the arc." Hmm. Let's find exact geometry. FIBA three-point line: arc center at basket; straight portions are at distance from sideline maybe 0.90 m. But there are interpretations. Let's search memory: In FIBA, three-point line distance from sideline: The lines parallel to the sideline? Actually the three-point line's straight parts are drawn parallel to the sidelines, but not necessarily; in many diagrams, the straight parts are perpendicular to the baseline. Wait think about basketball court side view: the three-point arc at top of key ends at the "wings". The straight portions run along the sides from baseline corners up to the wing, where they meet the arc. Are those straight lines parallel to the sideline or parallel to the baseline? They certainly look vertical (parallel to sideline) if court oriented with baseline horizontal. Yes, they run along the sides, parallel to sideline. In NBA, three-point straight lines are parallel to the sideline, 3 ft from sideline. In FIBA similarly, straight lines are parallel to sidelines at 0.90 m? So my x=0.90 assumption likely. But some diagrams show straight lines at 1.575? Actually meet the key? Let's verify with offset 0.90: endpoints at y=~2.99 as above. That seems low; the three-point line near the corner has significant straight segment of length ~3m before the arc starts around the wing. Is that right? NBA straight lines are 3 ft from sideline, arc radius 23.75 ft (7.24 m) at top of key? Actually NBA corner three distance is 22 ft from basket (6.71 m), so the straight segment from baseline is short (about 14.5 ft?). Wait NBA three-point line radius 23.75? Let's not. FIBA distance 6.75 m. A line 0.90 m from sideline intersects arc at y=~2.99, creating straight segment length ~3m from baseline. Arc then sweeps out from (0.90,2.99) around to (14.10,2.99). The three-point line's corner distance at baseline from sideline is 0.90? At the corner directly (x=0,y=0) is out of bounds; line begins at x=0.90 along baseline. This seems reasonable? But I think in FIBA the three-point line's straight part extends only from baseline to distance around 2.0m? Let's calculate offset for 0.75m: intersection y=sqrt(6.75^2-(7.5-0.75)^2)+1.575 = sqrt(45.56-45.5625)?? 6.75^2=45.5625; horizontal offset from basket 6.75 (if x=0.75). Exactly? (7.5-0.75)=6.75. Then y=1.575, so the straight line of 0.75 offset would meet the arc exactly at the baseline y=0? Wait because the point (x=0.75,y=0) distance to basket = sqrt(6.75^2 + 1.575^2) = 6.93 > 6.75, so not. Intersection y=1.575 means straight segment length 1.575. If offset 0.90, y=2.99. If offset 0.0 (sideline), arc not reached. So smaller offset => shorter straight segment. Which offset is correct? I recall the FIBA three-point line's straight line distance from the sideline is 0.90 m, and the straight parts are 2.99 m long? Maybe yes. But there is also "three-point line starts 1.575 m from inside edge of each endline?" Hmm. Let's search mental images of FIBA court. When viewing full court, the international three-point line looks like a big arc with sidelines straight segments, similar to NCAA/NBA but at 6.75m. The straight segment from baseline maybe around 3m. So 0.90 offset seems plausible. Many SVGs use x offset of 0.90m. Good. However, some FIBA diagrams define the three-point line as: two straight lines perpendicular to the endline, at a distance of 1.575 m from the inner edge of the endline? That's the distance to basket; weird. Need verified. Upon recalling FIBA official rule text: "The three-point field goal line is the radius of 6.75 m from the point on the floor vertically below the centre of the opponents' basket. The three-point line shall be marked as follows: - Two parallel lines perpendicular to the endline, at a distance of 0.90 m from the inner edge of each sideline. These lines are 2.35 m long. - An arc with a radius of 6.75 m from the point on the floor beneath the centre of the basket. The arc joins the parallel lines." Let's calculate line length if offset 0.90: from baseline y=0 to intersection y=2.991 => length ~2.99, not 2.35. If offset chosen so length 2.35, difference. There may be h gap. Let's see if line length 2.35, intersection point y=2.35. Offset = 7.5 - sqrt(6.75^2 - (2.35-1.575)^2). Compute dy=0.775. 6.75^2 - 0.775^2 =45.5625-0.600625=44.9619, sqrt=6.705, offset=0.795m. Not 0.90. If line length 2.35 from inner edge endline, then offset ~0.795. Hmm. Maybe the 0.90 is distance from the sideline to the straight section measured along the three-point line? Unclear. Let's search memory: FIBA three-point distance: "the two parallel lines are perpendicular to the endline, 0.90 m from the inner edge of the sidelines, with a length of 2.35 m." Wait if length is 2.35 and offset 0.90, geometry doesn't satisfy arc unless the straight lines don't go to baseline; maybe they start at baseline and extend 2.35, then the arc begins? But endpoint at (0.90,2.35) has distance to basket sqrt(6.6^2 + 0.775^2) = 6.645 <6.75, so endpoint is inside arc; the arc must then continue from that point outward. But the arc of radius 6.75 does not pass through that point. To join, the straight segment would need to be tangent? No. Alternatively, the straight lines are 0.90 m from the sideline and 2.35 m from the endline? That is the meet point; the line from (0.90,2.35) to (0.90,0) may not be part of the three-point line; maybe the three-point line begins at the baseline at x=0.90 and goes up 2.35 along sideline? But distance. Let's reconsider the FIBA three-point line construction: Perhaps the parallel straight lines start at the baseline and extend until they are 6.75 m from the basket center. That is exactly geometric: line x=sideOffset from y=0 to y where it touches the arc. The official sideOffset might be 0.90, leading to length ~2.99. That is not 2.35. So either sideOffset or length mem is wrong. Which is more likely? I recall FIBA three-point line parallel segment (corner distance) is about 3.02 m from baseline, and side distance 0.90 m. That seems correct. Let's see if actual total distance of three-point line from sideline to basket center at corner: The point where three-point line meets baseline is 0.90 m from sideline. The distance from basket to that baseline point is sqrt((7.5-0.9)^2 + 1.575^2)=sqrt(43.56+2.48)=sqrt(46.04)=6.785, slightly larger than 6.75. The line from baseline at x=0.90 upward eventually distance to basket decreases to 6.75 at y=2.99. Thus the baseline point is outside three-point territory; but the three-point line starts at baseline at x=0.90 because up to there the line is the sideline/out of bounds? Actually the three-point line at corner touches baseline at x=0.90? The distance at baseline (0.90,0) is 6.785>6.75, meaning (0.90,0) is beyond 3-point (distance >6.75) so a shot from there would be worth 3? Wait being behind three-point line means farther from basket than 6.75; so (0.90,0) is behind line. But the line begins there because moving perpendicularly inward at x=0.90 decreases distance; the set of points where distance equals 6.75 is at y=2.99. So from y=0 to y=2.99 on x=0.90, distance >6.75, these are 3-point region. Thus the three-point line includes the baseline segment from sideline to x=0.90? Actually the three-point region includes the entire corner up to baseline; the line runs along straight x=0.90 from baseline up. That matches typical diagrams: the corner 3 area extends all the way to the sideline and baseline. Good. So the straight segment length ~2.99 is plausible. Now, the FIBA three-point line may have a side offset equal to 0.90 m from the inner edge of sideline. This is what I will use. Need also the "throw-in division line?" FIBA also marks the center line extends to sidelines between endlines. Maybe optional. Need maybe basket/backboard representation? User asked field and lines; maybe include hoops/backboards as accurate. Could include backboards 1.20 m wide, protrude 1.20 m from baseline? Actually backboard support has length 0.15 m? Backboard plane is 1.20 m from baseline (outside court) in FIBA? In FIBA, distance from baseline to backboard is 1.20 m, and rim center 0.375 m from front plane, so basket center 1.575 m from baseline. We'll draw backboard as line segment just outside baseline at y=-1.20? Or small symbol. Could include the small basket center point? Use cross or dot at basket centers. Line widths: FIBA lines are 5 cm. In SVG user units (meters), stroke-width 0.05. But for lines, the playing area is measured to the inside edge of the line? We'll draw centers? For outer boundary, if line width 0.05, inner dimensions become 27.95 x14.95 if centered at 0/15. To be exact, maybe draw boundary using double lines or fill method: The court area is rectangle 28x15, line width drawn inside the boundary (inner edge). But visually difference negligible at scale. But "medidas perfectas reglamentarias" suggests should be exact. We can implement by drawing boundary lines with coordinates offset by 0.025, i.e., inside edge at 0 and outside at 0.05? Actually the playing court is the inner area; lines are inside the court? Typically lines are part of the playing court and 5 cm wide; inside edge of boundary is the limit. If we draw boundary line centered on x=0, then inner edge is 0.025 in, not exact. Better: draw boundary as a filled rectangle for the court area inclusive of lines? Approach: - Draw a rectangle with x=-0.05, y=-0.05, width=15.10, height=28.10 (line width outside), fill floor color. Then draw inner playing area rectangle at x=0,y=0,w=15,h=28 with no fill/stroke? Wait boundary line width should be 0.05; inside edge of boundary = court boundary. So draw rectangle with top-left (0,0) size (15,28), stroke-width 0.05, and then clip/align so stroke is centered -> outer half outside. If frame includes only from -0.05 to 15.05, inside is exact. For labels area, extend margin. For internal lines, we can draw with stroke width 0.05 center on theoretical positions; line width overlaps areas. That's acceptable. Can include dimensions labels for clarity. But "perfectas" maybe use labels not necessary. Let's create an HTML page with a centered SVG, maybe add some styling with dark background and light court. Use viewBox "-1.5 -1.5 18 31" (margin). Set width 100%, height auto. Use xmlns. Need to include title in Spanish. Use CSS to make responsive. Maybe add a legend. But keep simple. Need to decide whether to include all markings: lane spaces. If uncertain, include them at standard dimensions described by FIBA. Let's try to find exact lane space markings from official rules. FIBA 2022 rules diagram labels (likely) include "free-throw lane spaces" with positions: 1.75 m, 3.35 m, 4.60 m from baseline? Wait the distances between marked areas maybe 1.75m, 3.35m, 4.95m? Let's derive from known image. I recall a FIBA basketball court diagram lane markings along each lane line. There are 4 zones on each side? The key is 5.80 m long. Free throw line at 5.80. Lane spaces: - First (closest to baseline): from 1.75 to 2.60 (0.85 long). - Gap maybe 0.75 (to 3.35). Second from 3.35 to 4.20. - Third from 4.20 to 5.05? But free-throw line at 5.80, leaving 0.75. Hmm. I will look for a memory of specific FIBA dimensions: From a court markings table: - Lane line length: 5.80 - First lane space: 0.85 long, marked with its near edge 1.75 from endline. - Second lane space: 0.85 long, its near edge 0.85 from first? Actually spaces separated by 0.10 m? Hmm. Official FIBA free-throw diagram might be: "The first lane space shall be marked on each side of the lane, 1.75 m from the baseline, and shall be 0.85 m in length. The second lane space shall be marked 3.35 m from the baseline. The third lane space shall be marked 4.60 m from the baseline." If spaces are 0.85 long, that leaves: 1.75-2.60, gap 0.75 to 3.35? Wait gap 0.75; second 3.35-4.20, gap 0.40 to 4.60? third 4.60-5.45, gap 0.35 to 5.80 (free-throw line). Those gaps irregular. Maybe the marks are 0.10 m × 0.85 m, and the distances (centers?) to baseline: 1.80m, 3.00m, 4.20m? No. Let's search memory from diagrams: I see key with marks at roughly: near baseline there are two marks one above another, then a larger gap, then one near free throw line. Distances maybe 1.75 and 2.70 and 3.60? That is plausible: three marks equally-ish spaced: 1.75, 2.70 (diff 0.95), 3.60 (diff 0.90). Then free throw line 5.80 (gap 2.20). But the upper marks are too far from free throw line? Actually markings are only for positions of players along the lane. The first two near baseline are for defensive players; the one near free-throw line for offensive? Hmm. Let's check actual free-throw formation: During free throws, players occupy4 spaces along the lane: two closest to the baseline on each side are defensive, one next to each basket maybe? Wait: The free throw shooter takes free throw. Maximum of 5 players can line up along lane: 2 opponents nearest basket, next 2 opponents/team, then 2? FIBA: 6 players may occupy marked lane spaces: 2 on each side nearest the basket are opponents of shooter; 2 on each side next in line are teammates of shooter; and the remaining players stand behind the three-point line and center line. Actually along the lane, there are 6 spaces? Let's recall: The first space on either side (nearest basket) is 2.40 m? No. FIBA rule for free throws: "The first space for an opponent of the free-throw shooter shall be 1.75 m from the endline. The second space for a teammate of the free-throw shooter shall be directly above the first. The third space for an opponent shall be directly above the second." That implies 3 spaces per side, total 6 along the lane. That aligns with needing 3 marks per side. Distances from baseline to each? It might be 1.75, 2.60 (1.75+0.85), 3.45 (2.60+0.85)? Wait if each space length 0.85 and contiguous? But there must be gaps? Maybe the spaces themselves are 0.85 long and adjacent (touching) to form lane line segments. Then start positions: 1.75, 2.60, 3.45. Then from 3.45 to 5.80 free throw line =2.35. That is the "three-point" area. But are they contiguous? No, diagrams show small gaps between lane space marks because marks perpendicular to lane lines are only 10 cm wide and 85 cm long; the spaces between them perhaps 10 cm. Actually if lane spaces are for players, they are 85 cm long rectangles adjacent along lane line; line between them (gap) maybe not? Let's look at official rule in more detail. FIBA rule 2.4.5 Free-throw lane spaces: "The lane spaces for players during free throws shall be marked as follows: The first space nearest the endline on each side shall be 1.75 m from the inside edge of the endline and shall be 0.85 m long. The second space shall be 0.85 m long and shall be marked 0.85 m from the first space. The third space shall be 0.85 m long and shall be marked 0.85 m from the second space. All lane spaces are 0.10 m wide and shall be marked outside the restricted area." If that's true, starts at 1.75, 2.60, 3.45. That seems plausible and maybe exact. The 1.75, 2.60, 3.45 are positions of nearest edges. But I recall gap between spaces is 0.10? Let's verify. The rule likely requires the spaces be marked on both sides of the lane, each 0.85 m long × 0.10 m wide. The distance from the endline to the first mark is 1.75 m. The distance between marks? Might be 0.10 m? Hmm, if there are 3 spaces per side, maybe they are separated by 0.10 m gaps; starts: 1.75, 2.70, 3.65. That pattern matches earlier distances (1.75, 2.70, 3.60ish). The difference between first and second = 0.95 including 0.85+0.10 gap. But is this official? Not sure. Given time, perhaps omit lane space hash marks or include a conservative set that is clearly secondary and label it. The user only asked for court and lines, not player positions. But FIBA lines do include them. Could also provide note: Some markings like throw-in and team bench lines not included. Let's make robust code with accurate standard definitions from recognized source maybe National Federation? I can use EuroLeague/FIBA dimensions. There is known data used by many open source projects: SportTopology has FIBA basketball court dimensions: Court: 28x15 Center circle radius: 1.8 Freethrow lane width: 4.9, length: 5.8 Freethrow line: 3.6, radius: 1.8 Three point radius: 6.75, corner straight line length: 2.99, side offset? They list "threePointStraight": 2.992 (distance from baseline), "threePointSide": 0.90? "three-point line straight part: 2.992m; three-point line side part: 0.90m". Restricted area radius: 1.25. Lane space marks: maybe list positions (near baseline) at [1.75, 2.70, 3.60, 4.45] for 4 marks? Hmm. Actually a common open source library "basketball-court" uses lane space marks at [1.75, 2.70, 3.60, 4.45] maybe. But I'm not confident. Let's search from memory of a FIBA court vector I saw in Wikipedia: Basketball court dimensions.svg It shows lane space marks distances: 1.75 m, 2.70 m, 3.60 m, and 4.45 m maybe? It had 4 marks each side? Let me mentally recall Wikipedia's "Basketball court dimensions.svg": It includes measurements labels: "6.75m" three-point radius, "4.90m" key width, "5.80m" key, "3.60m" free throw line, "1.80m" center circle, and along lane lines marks numbered maybe distances 1.75, 3.35, 4.60. Hmm. Let's try to find from official rulebook if possible using known geometry of free-throw lane spaces: The lane spaces are marked on both sides of the free-throw lane. First space nearest the endline is 1.75 m from the inside edge of the endline. The width of the spaces is 0.10 m. The length of the spaces is 0.85 m. The distance between spaces? It's perhaps 0.10 m? No, the spaces are not separated by lines; each space itself is a line mark, not an area to occupy; they denote the 0.85m space between lane line and adjacent player. So marks represent areas e.g., first space from 1.75 to 2.60 (0.85), second from 2.70 to 3.55 (0.85), third from 3.65 to 4.50 (0.85). Then from top of third space (4.50) to free-throw line (5.80) is 1.30m reserved area. Is that plausible? Maybe. But why would spaces have 0.10m gaps? Because the 0.10m width of the mark itself is part of the 0.85m? Wait lane space mark is 0.10m wide line drawn outside the lane. The lane space itself (for a player) is 0.85m × 0.80m maybe; the mark is a line at one end of the space. There may be gaps between spaces. If spaces are for players, they shouldn't overlap, but can be adjacent. Let's check FIBA rule text if I can reconstruct: "The lane spaces shall be marked outside the restricted area. The first shall be 1.75 m from the endline, 0.85 m long. The second shall be 0.85 m from the first. The third shall be 0.85 m from the second." That would make starts: 1.75, 2.60, 3.45. But 0.85m from first to second could mean gap or start-to-start? If "shall be separated from each other by 0.85 m"? Hmm. Maybe search memory of official rule: "The spaces shall be marked as follows: - The first space on each side of the lane shall be 1.75 m from the inner edge of the endline and shall be 0.85 m in length. - The second space shall be 0.85 m in length and shall be marked 0.85 m from the first space. - The third space shall be 0.85 m in length and shall be marked 0.85 m from the second space. All spaces are 0.10 m in width." If start-to-start distance is 0.85, the spaces touch end-to-end. That means first 1.75-2.60, second 2.60-3.45, third 3.45-4.30. Then from 4.30 to free-throw line 5.80 =1.50. This leaves room for player(s) near top of key. But I think in real court the lane spaces are not touching; there are visible short gaps between the 0.85m rectangles. The Wikipedia diagram likely shows spaces at 1.75-2.60, 3.35-4.20, 4.95-5.80? That would be three spaces, each 0.85, first separated, and third reaching free throw line. Start positions: 1.75, 3.35, 4.95. Differences 1.60, 1.60. Those are starts 1.75, 3.35, 4.95. This pattern symmetrical within key length? 1.75 from baseline, 1.75 from free throw line? key length 5.80; free-throw line at 5.80; 5.80 - 0.85 = 4.95; 4.95-1.60=3.35; 3.35-1.60=1.75. Yes! This is elegant. So lane spaces are three per side, each 0.85m, positioned symmetrically: first 1.75–2.60 from endline, second 3.35–4.20, third 4.95–5.80 (touching free-throw line). Distances between spaces 0.75m? Actually gap between 2.60 and 3.35 =0.75; between 4.20 and 4.95 =0.75. This creates 0.75m gaps. Is that official? It seems plausible: from baseline to first space 1.75, between spaces 0.75, space length 0.85. Total =1.75 +0.85 +0.75 +0.85 +0.75 +0.85 =5.80. Nice! Sum: 1.75+0.85=2.60; +0.75=3.35; +0.85=4.20; +0.75=4.95; +0.85=5.80. Yes fits perfectly. This is likely the correct FIBA lane space arrangement. So lane space starts: 1.75, 3.35, 4.95. These are spaced 1.60 apart. This matches all dimensions integer/standard. So I'll use these. Good. Each lane space mark is a rectangle 0.85m long (along lane) by 0.10m wide (perpendicular, drawn outside the lane). The inner edge is at lane line, outer edge extends outward 0.10m. Wait "outside the restricted area" means on the side of lane line away from key. So mark centered or flush? It is a 0.10m wide stripe with inner edge along the lane line? Typically the lane space rectangles are drawn straddling lane line? Actually no, they are small lines perpendicular to lane line, 0.10m wide and 0.85m long, drawn on the outside of the lane. The line marking is like a T: a 10cm band, with one edge on lane line and extending outward 10cm; the 0.85m length runs along lane line. So for left lane line x=5.05, mark occupies x in [4.95? Wait outside left side is x < lane line? The lane extends from x=5.05 to x=9.95; left side outside is x<5.05. Mark extends 0.10m from lane line outward i.e., x in [4.95,5.05] (width 0.10). It is along lane line for y in [start, start+0.85]. For right lane line x=9.95, outside x in [9.95,10.05]. This is correct. We can draw 6 marks per end (3 each side). We'll use the start positions [1.75, 3.35, 4.95]. Good. Now three-point straight line length with offset 0.90 from sideline: start at baseline y=0 up to y where arc meets x=0.90. Need compute exactly. Let's calculate with Python? I can approximate manually. Center C=(7.5,1.575), R=6.75. Line x = 0.90 (left), x =14.10 (right). For left: dx = 7.5 - 0.90 = 6.6. dy = sqrt(R^2 - dx^2) = sqrt(45.5625 - 43.56) = sqrt(2.0025) = 1.415095... Actually sqrt(2.0025). 1.41509^2 =2.00248. So y = 1.575 + 1.4151 = 2.9901. So straight segment from y=0 to y=2.9901 at x=0.90. Actually baseline y=0, but the line meets baseline at exactly x=0.90? Yes. The arc starts at (0.90,2.990). Similarly mirror. Arc path: from left point to right point around the basket, passing through top of arc (center directly outward from basket). For bottom basket, the arc is the portion of circle for y >=2.99, consisting of points with center (7.5,1.575) radius 6.75, from angle? Left point angle = atan2(dy,dx_left?) dx = 0.90-7.5 = -6.6, dy=2.990-1.575=1.415, angle ~168°; right point angle ~12°. The arc passes through top point at (7.5, 1.575+6.75) = (7.5,8.325). So we can use path M (0.90, 2.990) A 6.75 6.75 0 0 0? Wait for bottom, starting left, going down? Let's define path as left endpoint -> arc to right endpoint, bulging away from baseline (toward center court). Starting at left x=0.90 y=2.990, arc should go upward through (7.5,8.325). For an SVG arc from start to end with radius 6.75, there are two arcs: large and small. Angle difference: from start angle ~168° to end angle ~12° going clockwise (decreasing angle) maybe 156°, which is the small arc (less than 180). The sweep flag determines which of two possible arcs (depending on direction). Let's compute with SVG A relative coordinates: path M left L (0.90,0) maybe include baseline? Then three-point line should include baseline segment from sideline to offset? Actually the shape is closed? The line just the line; it includes the straight segments and arc. Starting at baseline left corner (x=0.90,y=0), line up to (0.90,2.990), arc to (14.10,2.990), line down to (14.10,0) (baseline). This forms a continuous line. But note the segment (0,0)-(0.90,0) along baseline? Is that part of three-point line? The baseline itself is boundary; the three-point line starts at the intersection with baseline at x=0.90. Actually the line as marked includes a segment of 8.5? Wait earlier I said line begins at x=0.90 on baseline. That segment from sideline to x=0.90 is just baseline, not part of three-point line. But in many diagrams, three-point line includes a straight line perpendicular to baseline from baseline to arc at x=0.90. So start at (0.90,0). Good. In SVG, draw three-point path: M 0.90 0 L 0.90 2.990 A 6.75 6.75 0 0 0? Need to choose sweep flag to go upward/through (7.5,8.325) from left to right. Starting at left angle 168°, ending at right angle 12°. If we use 0 large-arc-flag, sweep-flag 1? Let's think. SVG arc: from start to end, with radii rx,ry. The elliptical arc has two flags: large-arc-flag (0 for small angle <180), sweep-flag (1 for "positive-angle direction", i.e. clockwise? Actually SVG positive angle direction is from positive x toward positive y, i.e., clockwise? Wait SVG coordinate system y downward if not transformed. In viewBox with y increasing downward, angles rotate clockwise (positive). But the geometry is just geometry: sweep-flag=1 draws the arc in "positive angle" direction from start point to end point. We want the arc that passes below? Starting at left (168°) moving toward right (12°); one direction is decreasing angle through 180? Actually angles modulo 360. Direction via positive angle from 168° to 12°: goes 168→360→12 = 204°, large. Direction via negative from 168 to 12 = -156° (or 204° the other way). With sweep flag = 0, we go the short arc with central angle -156° (clockwise in screen coords), which goes through angle 168° down to 12°, passing through 90° maybe? Let's see angles in screen coords: angle 90° is at (7.5,8.325) (y beyond center). Starting 168, decreasing angle passes through 90 to 12. Yes. In SVG with sweep flag 0 chooses the arc in negative-angle direction, which passes through lower y? Wait in screen coords y down, positive angle from positive x axis points down. Angle 90 points straight down (toward baseline). But our point (7.5,8.325) has angle atan2(y-centerY, x-centerX). Since centerY=1.575, point y=8.325, dy=6.75 positive (downward). Angle is +90° (clockwise). Starting angle left point: dx=-6.6, dy=1.415 positive, angle ~168°. Ending angle right: dx=6.6, dy=1.415, angle ~12°. To go from 168° to 12° passing through 90° (downward/increasing y), we go in decreasing angle modulo 360? Actually decreasing from 168 to 12 passes through 90? 168->167...->90...->12. Yes exactly. In SVG screen coords, decreasing angle corresponds to sweep-flag=1? Need clarify. Usually for a circle centered at (cx,cy) in standard Cartesian (y up), arc with sweep-flag 1 goes clockwise in SVG because y axis inverted? I always test: path M 0 50 A 50 50 0 0 1 100 50 draws the bottom half of a circle in SVG (since y positive down). Standard circle center (50,50) radius 50: top of circle at (50,0). Path from (0,50) to (100,50) with sweep 1 draws lower semicircle (through (50,100)). That is clockwise in screen coords (from left around bottom to right). Standard angles from center (50,50): left point angle 180° (or π), right point 0° (or 2π). Going clockwise from 180° to 360°/0° passes through 270° (down). sweep-flag=1 is clockwise. Our coordinates center (7.5,1.575): left point angle relative to center in screen coords is atan2(dy=1.415 positive, dx=-6.6) ≈ 168°; right point angle atan2(1.415,6.6)=12°. Clockwise from 168° to 12° would go 168->90->12 (decreasing angle), passes through y larger at 90°, correct. So sweep-flag=1, large-arc-flag=0 (central angle 156° <180). Good. So A command: A 6.75 6.75 0 0 1 14.10 2.990. Then L 14.10 0. For top end, orientation mirrored. Center (7.5,26.425), straight segments at x=0.90 and 14.10 from y=28 to y=25.0099 (since arc inside court toward center). Arc top point (7.5, 26.425-6.75)= (7.5,19.675). Path: M 0.90 28 L 0.90 25.010 A 6.75 6.75 0 0 1? Now left point relative center: dx=-6.6, dy=(25.010-26.425)=-1.415 (up), angle in screen coords = atan2(-1.415,-6.6)= -168°/192°; right angle atan2(-1.415,6.6)= -12°/348°. Arc passing through top point (7.5,19.675): angle -90° (up). Clockwise from left (-168°) to right (-12°)? Clockwise passes through -90°, i.e., central angle 156°, sweep-flag=1. But if using SVG positive sweep flag clockwise, from start (left) to end (right): angle difference clockwise = -12 - (-168) = 156° (positive as clockwise direction). So sweep=1, large=0. However note dy is negative; start point (0.90,25.010). Command A radius 6.75 6.75 0 0 1 14.10 25.010. Good. Free-throw circle: bottom center (7.5,5.8). Inside-lane part is y<5.8 (toward baseline), outside-lane part y>5.8 (toward center court). Draw dashed arc from left lane intersection to right at y=5.8? The full circle radius 1.8. Intersections with lane lines at x=5.05 and 9.95 along y=5.8. We can draw a full circle, then clip? Easier: Draw two arcs: - Dashed inside key: half circle for y<5.8, from (9.95,5.8) to (5.05,5.8) passing through (7.5,4.0). With proper sweep. - Solid outside key: half circle for y>5.8, from (5.05,5.8) to (9.95,5.8) passing through (7.5,7.6). At top similarly. Alternatively, draw full circle with stroke-dasharray to create dashed half? Too hard. Use arcs. Need to be careful with arc direction: bottom dashed arc: center (7.5,5.8), left contact (5.05,5.8), right (9.95,5.8). The inside (toward baseline) half has y increasing? Baseline y=0 lower; inside key is below center y=5.8 (y larger since y increases downward). Wait y axis positive downward; baseline at y=0; center at y=5.8. Inside key is y>5.8? No, key from baseline y=0 to free throw line y=5.8. Points inside key have y between 0 and 5.8. The free throw circle center is at the free throw line y=5.8, so inside-key portion is y>5.8? That goes outside key (toward center court). But key is below the free throw line (y<5.8) because baseline y=0. Wait coordinate: y=0 is bottom baseline, y increases going up the page? The user might view y increasing downward by default if not careful. Need decide orientation. In SVG, y increases downward by default, but it's just coordinate system; we can set y=0 at bottom baseline and y=28 at top baseline, so y increases upward from bottom. Actually typical SVG viewBox y increases downward, but we can define viewBox where y coordinate corresponds to real court with bottom baseline at larger y? It doesn't matter as long as consistent. To avoid confusion, let's set origin at the top-left of the court with y increasing downward (standard SVG), and draw top baseline at y=0, bottom baseline at y=28. That means "bottom end" is physically at y=28 (closer to bottom of screen). Baskets at y=1.575 (top) and y=26.425 (bottom). Then key for top basket extends downward to y=5.8; key for bottom basket extends upward to y=22.2. This is more natural with default y. Good. Let's adopt top baseline y=0, bottom baseline y=28. Then for top end, basket at y=1.575, free throw line y=5.8, key extends down from top baseline to y=5.8. For bottom end, basket y=26.425, free throw line y=22.2, key extends up from y=28 to y=22.2. With this orientation, earlier calculations for bottom need swap. Let's recompute consistently: Coordinates: - x: 0 left sideline, 15 right sideline. - y: 0 top baseline, 28 bottom baseline. - Top basket center: (7.5,1.575). - Bottom basket center: (7.5,26.425). Three-point line for top: - Straight side lines from baseline y=0 upward: x=0.90 and x=14.10. Arc center (7.5,1.575) radius 6.75. Intersection y = 1.575 + sqrt(6.75^2 - 6.6^2) = 2.990. So straight segment y=0 to y=2.990. Arc from left (0.90,2.990) to right (14.10,2.990) passing through outer point (7.5,1.575+6.75=8.325). The arc goes away from baseline (downward). With sweep-flag 1? Same analysis: left angle screen ~168°, right ~12°, clockwise through 90° (down) = sweep=1, large=0. Path top: M 0.90 0 L 0.90 2.990 A 6.75 6.75 0 0 1 14.10 2.990 L 14.10 0. For bottom: straight side lines from baseline y=28 downward: x=0.90 and x=14.10. Intersection y = 26.425 - sqrt(6.75^2 - 6.6^2) = 25.010. Arc from left (0.90,25.010) to right (14.10,25.010) passing through (7.5,26.425-6.75=19.675). Path: M 0.90 28 L 0.90 25.010 A 6.75 6.75 0 0 1 14.10 25.010 L 14.10 28. Need check: left point relative center dx=-6.6, dy=-1.415 => angle ~192° (-168°). right ~348° (-12°). Clockwise from 192° to 348° passes through 270° (up), yes sweep=1. Free-throw circle top: - Center (7.5,5.8). Inside key = y<5.8 (toward baseline/top). Outside key = y>5.8 (toward center). Lane lines x=5.05,9.95; free throw line y=5.8 connects them. The free throw circle radius 1.80. Draw dashed arc inside key (above center y<5.8 i.e., y decreasing) from right (9.95,5.8) to left (5.05,5.8) through (7.5,4.0). Draw solid arc outside key (below center y>5.8) from left to right through (7.5,7.6). Bottom center (7.5,22.2). Inside key = y>22.2 (toward baseline/bottom). Outside key = y<22.2 (toward center). Dashed arc inside from left to right? Let's just define paths. No-charge semicircle top: - Radius 1.25 centered at basket (7.5,1.575), arc toward baseline (upward y<1.575), with diameter along y=1.575, endpoints (6.25,1.575) and (8.75,1.575). Arc passes through (7.5,0.325). Path: M(6.25,1.575) A 1.25 1.25 0 0 0? Need determine: start left (6.25,1.575) angle 180° (or π), end (8.75,1.575) angle 0°. To pass through (7.5,0.325) which is y below center (up on screen) = angle 270° (or -90°). Going from 180° to 0° clockwise passes through 270°, sweep=1, large=0. But note the arc is small (180°) exactly a semicircle. large-arc-flag=0 means small (<180), but semicircle ambiguous; for 180°, flags maybe 0 1. We'll set A 1.25 1.25 0 0 1 8.75 1.575. That draws bottom? Wait in screen coords, sweep=1 from left angle 180° to 0° goes through 270° (down = positive y) or 90° (up = negative y)? Let's test with point below center (y larger) at angle +90? Using screen y positive downward, angle from positive x-axis rotating clockwise: up is -90/270°, down is +90°. Wait earlier for top three-point, point (7.5,8.325) relative center (1.575) dy positive downward = 6.75, angle = -? atan2(y=6.75,x=0) = 90°. So +90° means down (toward center of court). For top basket, baseline is up (negative y), angle -90°/270°. So for no-charge at top, arc toward baseline is upward, point (7.5,0.325) has dy=-1.25, angle = -90° (or 270°). Starting at left point angle 180°, ending at 0°. To pass through 270°, we need clockwise from 180° to 0°? Clockwise from 180 decreasing to 0 passes through 90°, not 270°. Counter-clockwise (sweep=0) from 180° to 0° goes through 270°. So for top no-charge (toward baseline, up), sweep should be 0. Good catch. Let's reason systematically for arcs: - Bottom no-charge at bottom basket (7.5,26.425), arc toward baseline (downward y larger). Point (7.5,27.675) maybe dy=+1.25. Start left (6.25,26.425) angle 180°, end right (8.75,26.425) 0°. Clockwise from 180 to 0 passes through +90 (down), so sweep=1. - Top no-charge at top basket, arc toward baseline (upward y smaller). Start left angle 180, end 0, counter-clockwise through -90, sweep=0. Thus use sweep accordingly. No-charge line is solid maybe. FIBA rule maybe line ends on baseline? But our geometry is standard. Center line: y=14 line from x=0 to 15. Center circle: center (7.5,14) radius 1.8, full circle solid. Free-throw arc (circle) dashed/solid. We must also make sure the free-throw line is separate from lane rectangle; lane rectangle top y=5.8 includes the free-throw line segment from x=5.05 to9.95. We can draw key rectangle (not stroke) with lines. But include solid free-throw line. The free throw circle solid part outside key: it connects lane lines at free throw line. The dashed part inside key goes from right lane line to left lane line under basket. Actually the free throw circle is drawn with the part inside the restricted area as dashed. The restricted area is the lane/key. The part of the circle inside key (towards baseline) should be dashed; outside key solid. Top end: dashed arc above free-throw line (y<5.8), solid below (y>5.8). We'll draw: - Solid: path from (5.05,5.8) A 1.8 1.8 0 0 1 9.95 5.8 (passing through 7.5,7.6). sweep? Starting left (5.05) angle 180°, ending right (9.95) angle 0°, passing through down (+90) y=7.6 => clockwise sweep=1. large=0. Good. - Dashed: path from (9.95,5.8) A 1.8 1.8 0 0 1 5.05 5.8? Passing through up (-90) y=4.0 => from right angle 0° to left 180° counter-clockwise through -90 => sweep=0. Or from left to right with sweep? Let's choose from right to left sweep=0. Bottom end: center (7.5,22.2); solid part outside key above? Actually outside key is toward center court (y smaller). Solid arc from (5.05,22.2) to (9.95,22.2) passing through (7.5,20.4) (up). Start left angle 180, end 0, through -90 => counter-clockwise sweep=0. Dashed inside key below free throw line: from (9.95,22.2) to (5.05,22.2) passing through (7.5,24.0) (down) => sweep=1. Could also draw full circles and use clipPath. Let's implement with arcs. Basket/backboard: - Backboard is 1.20 m wide, positioned 1.20 m outside each baseline? Actually the backboard plane is 1.20 m from inside edge of endline (outside court). Backboard centered on basket x=7.5, so x endpoints 6.90 and 8.10. y coordinate = -0.15? But the backboard protrudes outside endline; if y=0 baseline, backboard is at y=-1.20? Hmm physical: endline is at y=0; the backboard's inside face is 1.20 m outside the endline, so its y = -1.20. The basket center is 0.375 m in front of backboard, i.e., farther into court at y=1.575 (inside). Wait if backboard outside at y=-1.20, basket center at 0.375m in front => y=-1.20+0.375 = -0.825? That can't be inside court (negative). Wait wrong orientation. In basketball, the backboard is behind the basket, behind the baseline? Actually the basket is attached to the backboard; the backboard is 1.2m inside the court from the baseline? Let's recall: The backboard support is mounted behind the baseline; the backboard face overhangs onto the court? No, the backboard is outside the court, behind the baseline. The basket ring is 0.375 m from the backboard face toward court. The distance from the inside edge of the endline to the basket center is 1.575 m. Therefore the backboard face is 1.575 - 0.375 = 1.20 m from the inside edge of the endline, outside the court. Yes: inside court endline y=0, backboard outside at y = -1.20 (if outside is negative), basket center at y=1.575 (inside court). That makes sense: the basket is inside the court by 1.575 m from baseline; the backboard is behind the baseline by 1.20 m. So basket center is 2.775 m from backboard? Wait if backboard is -1.20 and basket center +1.575, distance between =2.775 m. But the ring is 0.375 m from the front of backboard in the horizontal? The horizontal projection of ring center from backboard plane is 0.375 m. Where does 2.775 come from? Something off. Actual: Backboard is 1.2 m from the endline? Or maybe the backboard overhang is 1.2 m from the center of basket? No. Regulation: The backboard protrudes 4 ft into court? Wait I think the backboard is positioned with its face 4 ft (1.22 m) from the endline (inside the court) in NBA? Actually the distance from the baseline to the front face of the backboard is 4 ft (1.22 m), and the rim center is 6 inches in front of backboard = 4 ft 6 in (1.3716 m) from baseline. But in FIBA, the distance from endline to basket center is 1.575 m? Let's verify. Maybe FIBA basket center is 1.575 m from endline and backboard face is 1.20 m from endline, but the ring center is 0.375 m from backboard face toward court. Then distance from baseline to ring = backboard distance from baseline + 0.375 = 1.575 (if backboard at 1.20 from baseline inside court). That implies backboard is inside the court, not outside! Because the rim is in front of backboard toward the middle; if backboard is outside (behind baseline), rim would be even farther outside plus 0.375, but the actual rim is inside court. So the backboard must be positioned such that its front face is 0.375m behind the rim (toward baseline), and the rim is 1.575m from baseline. Thus backboard face is 1.575 - 0.375 = 1.20 m from baseline, inside the court. Yes! The backboard overhangs into the court, with its face 1.20 m from the endline. The support is outside. So backboard face is in-court. In many diagrams, backboard is drawn at y=0? Actually baseline passes under the backboard? The backboard face is behind the rim but still inbounds? The baseline is the boundary at the end of court. The backboard is above the baseline? The endline at y=0; the front face of the backboard is 1.2 m behind the rim but still perhaps outside the court? Let's think physically: Basketball court has endline. The basket is mounted on a support behind the baseline; the backboard face is 4 ft (1.22m) inside/overhang above the court from the endline. Actually official: "The backboard shall be positioned at the endline with the front face of the backboard 1.20 m from the inner edge of the endline." This means the backboard overhangs onto the court? The inner edge of endline is the boundary; front face 1.20 m from that edge into the court. The rim center is 0.375 m from front face towards the midline, so distance from endline to rim = 1.575 m. This is standard. The backboard is inside/outside? It extends above the out-of-bounds area beyond the endline too; the support is outside, but face is measured into court. In court diagrams, the basket/backboard is drawn just outside the boundary line? Many sports diagrams show basket at 1.575m from baseline inside the court, backboard as a line at baseline? They often show backboard as a small rectangle at y=0 (baseline). But to be accurate, maybe draw rim center point and backboard line at y=-0.15? Wait 1.575 - 0.375 =1.20 from endline; but backboard face itself could be considered at y=-1.20 if baseline is at y=0? Let's physically define y=0 as inside edge of endline (the in-bounds court starts at y=0). The court behind baseline (out of bounds) has negative y. The backboard front face is 1.20 m inside the court, i.e., at y=+1.20 (in-bounds). The rim center is 0.375 m further into court at y=1.575. Does the backboard face lie inside the court, not behind baseline? Yes. The baseline line runs under the bottom of backboard? The backboard lower edge is 2.90m above floor, so floor line at y=0 is at the base of backboard support; front face projection at y=1.2 on the floor. So in some diagrams, backboard is shown as a line at y=0 (baseline) for simplification, and basket at y=1.575. To be accurate, show backboard projection at y=1.2? Is that known? Actually FIBA rules define distance from endline to center of basket 1.575; to front of backboard 1.2. The endline is at y=0. So backboard front at y=1.2, rim at y=1.575. But typical court floor markings do not include the backboard; we can omit or show a small line symbol at x=7.5±0.6 y=1.2 (if desired). The user asked for court and lines; perhaps basket/backboard optional. Maybe it is cleaner to show backboard as line segment at 1.2m from baseline inside court, and rim center dot at 1.575m. Provide comments. If we draw backboard at y=0, it's wrong by 1.2m. But a 2D court plan includes the backboard position. Let's include backboards at y=1.2 and y=26.8 (since 28 -1.2), centered, width 1.2 (x±0.6). Use thicker line or rectangle. Then basket center dot/mark at y=1.575 and 26.425. Need "centre line", "centre circle". Potential issue: The lane/key usually is called "restricted area" not no-charge. We'll label maybe. What about the "throw-in lines" (centre line extensions), "substitution area" etc. Not needed. To make it pretty and accurate, we can generate a full HTML page with a title in Spanish, an SVG and maybe small legend explaining dimensions. The user wants only SVG and lines; but adding interactive rendering and labels beneficial. However they may want just the SVG code. Since they want render in iframe, I can provide full HTML with inline SVG. Need to include all SVG in one code block. Ensure no external libraries. Use internal CSS for body centering. Use viewBox with margins for labels. If we include labels, we need font; use system-ui sans-serif. Add text elements with dimensions maybe. Let's draft code. Use JavaScript? Could use script to compute variables and generate SVG dynamically, but that might be overkill; script can generate paths easily. But the requirement says if any external libs include full HTML; no external libs. We can use static SVG with paths, simpler. However, using static paths with many arcs, coordinate calculations could be error-prone. Could embed a small JS to compute and draw at load time, with code creating SVG elements. That might be easier and guarantees geometry; also full HTML. But pure static SVG simpler for view and no script. The user didn't forbid JS. But a static SVG would display even if JS disabled. Let's produce static SVG with comments. Use maybe manual computed values. Ensure arcs correct. We need to avoid referring to iframe. Let's plan SVG structure: ``` Cancha FIBA SVG

Cancha de baloncesto FIBA (28 m × 15 m)

Medidas según Reglamento FIBA actual (líneas de 5 cm).

``` We need `viewBox` dimensions: court width 15 + margins. Add margin 2 on each side maybe. `viewBox="-2 -2 19 32"` width 19, height 32. That is fine. But background rect can be full court area, line strokes at 0.05. The container width responsive. For label fonts, set font-size relative to meters 0.3-0.4; 0.35 m is 35cm on court, too big. Use 0.25 m (25cm) for labels. Good. Dashed line style: FIBA dashed line for free-throw circle inside restricted area: dashes likely 0.20 m long and gaps 0.10 m? Actually FIBA rule: dashed lines in free-throw circle are 0.05 m wide and the gaps and dashes maybe 0.10? Not critical. Use `stroke-dasharray="0.15,0.15"` looks okay. Arc for free-throw circle: need to be drawn after lane lines so they overlay. Order doesn't matter much. Three-point line: should be 0.05 wide, white. Need to clip boundary lines? We could use markers. Let's draw boundary as rectangle with stroke width 0.05 and no fill, centered at (0,0,15,28). That gives inner area 15x28 exactly if half the stroke extends outside viewBox? But if fill none and stroke extends outside, the visible inner edge is at 0.025 in; not exact. To be visually exact, we can draw the boundary as four lines with inside edges: left line x=0 from y=0 to y=28 stroke width 0.05 (center at x=0.025? no). If we want inside edge at x=0, line center at x=0.025. But then outside edge at x=-0.05. Better with fill rectangle: draw a rectangle at x=0,y=0 width=15,height=28 with stroke="#fff" stroke-width=0.05 and fill="#d2a679". Since SVG strokes are centered, the inside edge is at 0.025. To make exact, set `path` with a stroke that lies inside, or use `fill` for court area with no boundary stroke and then outline outside? We could draw a filled rectangle with half stroke outside and set `vector-effect="non-scaling-stroke"` not needed. For precise, define path that traces inner boundary and use stroke-width*2? Hmm. The line itself (5cm) is supposed to be in-bounds. The inner edge of the line is the boundary; if we set the line center along the boundary, half of line is outside court. Regulation lines are all 5 cm wide and included within the playing court? Actually the lines are inside the court, so boundary line's outer edge maybe coincides with boundary? FIBA rule: "The lines shall be 5 cm wide and of the same colour. They must be clearly visible. The lines are part of the playing court." It doesn't say the outer edge; lines must be inside? Typical marking: the inside edge of the boundary line is the limit. But for a diagram, it's fine. We can draw boundary as a thick filled rectangle floor color with a stroke aligned to inside. Simpler: Use `rect x="0" y="0" width="15" height="28" fill="#d69c5b" stroke="#fff" stroke-width="0.05"`. The actual in-bounds area inner edge is offset by 0.025; at typical scale negligible. We may mention line width 5 cm. Also maybe use `stroke-linecap` not relevant. Alternatively, to make inside dimensions perfect, set rect x="0.025" y="0.025" width="14.95" height="27.95" with stroke-width 0.05, so inner area is exactly 14.95? Hmm not. Maybe the simplest is to not overengineer. Use rect at 0,0 with stroke. Fine. Now geometry values in terms of variables: - W=15, H=28. - basketY_top=1.575, basketY_bottom=26.425. - keyWidth=4.90 => x_lane_left=7.5-2.45=5.05, x_lane_right=9.95. - keyLengthTop=5.80, top free throw line y=5.8, bottom key y=22.2. - centerY=14. - centerCircleR=1.8. - freeThrowCircleR=1.8. - threePointR=6.75, threePointSideOffset=0.90, threePointStraightIntersect=1.575+sqrt(...) = 2.990095... Use 2.990. - restrictedR=1.25. Lane space starts: [1.75,3.35,4.95]. Mark length along y=0.85. Mark width outward=0.10. Need mark y from start to start+0.85. For top end, mark drawn within key length 0..5.8. At y positions from baseline: 1.75-2.60, 3.35-4.20, 4.95-5.80. Good symmetrical. For bottom end mirrored: key extends from y=28 down to y=22.2 (length 5.8). The lane spaces are measured from bottom baseline (y=28) inward. Positions y = 28 - start to 28 - (start+0.85). So start 1.75 => y 26.25 to 25.40; wait 28-1.75=26.25, 28-2.60=25.40. That's a rectangle near baseline. 3.35 => 24.65 to 23.80. 4.95 => 23.05 to22.20 (touching free throw line). Good. Backboard position: y=1.2 top, y=26.8 bottom, centered x=7.5, width 1.2 -> x from 6.9 to 8.1. Rim dot radius maybe 0.04 at (7.5,1.575)/(7.5,26.425). Some diagrams show backboard line spanning 1.2. We'll draw a line of width 0.08. Now, need include team bench/throw-in markings? No. Dimension labels optional. Maybe include a small set of labels to show medidas. For example, label "28 m" on right side, "15 m" at top, "6,75 m" for arc radius maybe. But maybe overcomplicates. Let's include few key labels on SVG to emphasize regulation. Use text. Since background tan and white lines, text could be dark grey. Use positions with transforms. However, adding dimension arrows may clutter. We can keep minimal: bottom note. Let's produce the code. Need to verify arcs commands. Let's write SVG paths carefully: Court boundary: `` Centre line: `` Centre circle: `` Lanes: `` left top, right top, left bottom, right bottom. Free throw lines: `` and bottom y=22.2. Free-throw circles: Top solid: path d="M 5.05 5.8 A 1.8 1.8 0 0 1 9.95 5.8". Top dashed: path d="M 9.95 5.8 A 1.8 1.8 0 0 0 5.05 5.8". Because from right to left passing through (7.5,4.0) up (negative y). Starting at right (9.95) angle 0°, ending left angle 180°. Counter-clockwise (sweep=0) passes through -90° (y smaller). Good. Bottom solid: path d="M 5.05 22.2 A 1.8 1.8 0 0 0 9.95 22.2" (through y=20.4 smaller). Starting left angle 180, ending right 0, counter-clockwise passes through -90. yes sweep=0. Bottom dashed: path d="M 9.95 22.2 A 1.8 1.8 0 0 1 5.05 22.2" (through 24.0). Good. Restricted area (no-charge) semicircles: Top: d="M 6.25 1.575 A 1.25 1.25 0 0 0 8.75 1.575". Start left angle 180°, end right 0°, sweep=0 -> goes through -90° up (toward baseline). Good. Bottom: d="M 6.25 26.425 A 1.25 1.25 0 0 1 8.75 26.425". sweep=1 -> through +90° down. Good. Three-point lines: Top: d="M 0.90 0 L 0.90 2.990 A 6.75 6.75 0 0 1 14.10 2.990 L 14.10 0". Sweep? We determined sweep=1 clockwise passing through +90 (down) for top arc. Yes. From left angle 168° to right 12° clockwise through 90 (down). Sweep=1. Good. Bottom: d="M 0.90 28 L 0.90 25.010 A 6.75 6.75 0 0 1 14.10 25.010 L 14.10 28". Start left relative center dx=-6.6, dy=-1.415 -> angle ≈ 192°; end 348°; clockwise through 270° (-90 up) to center court (y=19.675) which is upward (smaller y). Wait for bottom, the arc toward center is upward (y=19.675), which is angle relative center = -90° (270°). Starting at 192°, clockwise through 270° to 348° is sweep=1. Good. But wait for top, center of arc (7.5,1.575), outer point y=8.325 (down) angle +90. Clockwise from 168 to 12 passes through 90 => sweep=1. Yes. For bottom center (7.5,26.425), outer point y=19.675 (up) angle -90 (=270). Starting left 192, clockwise through 270 to 348 => sweep=1. Good. Lane space marks: Need rectangle? Use line/rect. Easier: draw small rectangles (fill white) length 0.85 along lane line, width 0.10 outward. For top left lane line at x=5.05, outside is left (x decreasing), so rect x=4.95, y=1.75, width=0.10, height=0.85. Right outside x increasing: x=9.95,y=1.75,width=0.10,height=0.85. Then second y=3.35, third y=4.95. Bottom: rectangles outside lane lines measured from bottom baseline. For bottom left lane x=5.05, outside x=4.95, y=28 - (start+0.85) to start? To represent, rect x=4.95, y=28-2.60=25.40, width=0.10,height=0.85? Wait start 1.75 from bottom baseline => rectangle from y=26.25 down to y=25.40. Since y increases downward, y top = 26.25, height=0.85. Yes. `y=28 - (1.75+0.85)=25.40`, height=0.85. For start 3.35 => y=28-4.20=23.80; start 4.95 => y=28-5.80=22.20. Good. For right bottom, x=9.95. Backboards and rims: Top: line x1=6.9 y1=1.2 x2=8.1 y2=1.2, maybe backboard; dot at (7.5,1.575) radius 0.03. Bottom: line y=26.8; dot (7.5,26.425) radius 0.03. Potential nuance: The free-throw circle dashed inside lane may overlap the no-charge semicircle? Not overlap because no-charge around basket y=1.575 radius 1.25 reaches y=0.325, while dashed free throw circle center y=5.8 radius 1.8 near y=4.0, no overlap. Good. Need also "center line" line width 0.05; the centre circle crosses center line; it's fine. If we draw the court boundary last? The order of drawing means stroke over other? We might want lines on top of floor. No issue. Should the free throw line be part of the key rectangle; independent line duplicate. Good. One more thing: FIBA key has lines at the inner edge. Lane lines are 5cm, etc. We're drawing them as simple lines. They intersect at corners; line join could produce overhang. Use `stroke-linejoin="miter"`, default. Fine. Could also add the three-point line's straight lines along baseline? No. Maybe should add the small lines extending from the no-charge semicircle? FIBA no-charge zone is bounded by the semicircle and two parallel lines perpendicular to baseline of length 0.375 m, ending 1.20 m from baseline? Let me revisit. Actually the no-charge semicircle might include a small rectangle extending to baseline, not just a half circle. Let's check official rule to ensure accuracy. I will try to recall exact FIBA no-charge area diagram. In a FIBA court drawing, under each basket there is a small semicircle line with radius 1.25 m, and there are two short lines (0.375 m) perpendicular to the endline, connecting the ends of the semicircle to the endline? Wait, a semicircle of radius 1.25 m centered at basket (1.575 from endline) does not reach endline, so perhaps the rule says the semicircle line ends with two perpendicular lines of length 0.375 m that connect the endpoints of the semicircle to the endline, making a closed area. Let's compute: endpoints at (6.25,1.575) and (8.75,1.575). Lines perpendicular to endline (vertical) from these points to endline y=0 length 1.575, not 0.375. So not 0.375. Maybe the no-charge semicircle is centered at y=0.325? If center is 1.25 m from baseline? Let's examine if center of no-charge semicircle is at the point where? Could be the point on the floor beneath the front of the rim? The distance from baseline to front of rim/backboard? Hmm. Let's search memory more accurately: FIBA rule 2.4.7 "No-charge semi-circle areas" maybe diagram: A semi-circle with radius 1.25 m measured from the point on the floor beneath the exact centre of the basket. The semi-circle is joined to two lines that are: - 0.375 m in length - perpendicular to the endline - each ending 1.20 m from the inner edge of the endline. What does ending 1.20m from endline mean? An L-shaped boundary? I might be mixing with the restricted area in wheelchair basketball. Hmm. Let's search memory of actual FIBA court image: Under the basket, inside the key, there is a small dashed? Actually FIBA no-charge semicircle line is drawn as a solid line, a half-circle around the basket, with its flat side parallel to the baseline passing through the basket center. There are no additional lines. I think that's the standard. It is exactly a half disk. I'll go with that. The user wants "medidas perfectas reglamentarias". If I omit the short perpendicular lines incorrectly, it's okay; the no-charge semicircle is the primary marking. Need to ensure the three-point line uses metric units 6.75 and side offset 0.90. But maybe the FIBA three-point line side offset is 0.90 m from inner edge of sideline. Use that. Could there be a "centre circle" line and "centre line" line; both width 5 cm. Let's finalize the HTML. I should include comments in Spanish or English documenting dimensions. Potential problem: We used `stroke-dasharray="0.15,0.15"` for dashed arcs, but making arc path with dash will also dash? Yes. We need to apply class "dashed" to those arcs. The three-point line is continuous. The rest solid. We may also need to draw the no-charge line as solid and maybe thicker? Keep same 0.05. Dimension labels: Let's add little annotations maybe near margins showing basic measures: "28 m" vertical, "15 m" horizontal, "6,75 m" near three-point arc. These labels can be black or dark to appear outside? We have viewBox margin -2. Maybe place labels outside. Use `text` with font-size 0.4. This might improve value. But could clutter. Maybe just a title and note. Let's keep clean. Let's add a small legend maybe not needed. Need to output in Spanish; before code block some intro. Then the code block contains full HTML. The code block should start with `` etc. Wrap in markdown `html`. Ensure no external dependencies. Need to verify arc sign for free-throw dashed top. Let's test mentally by drawing: Top center at (7.5,5.8). Solid arc below center (y increasing) from left to right with sweep=1: path M 5.05 5.8 A 1.8 1.8 0 0 1 9.95 5.8. This draws the lower semicircle (toward center court). Dashed arc above center (y decreasing) from right to left with sweep=0: M 9.95 5.8 A 1.8 1.8 0 0 0 5.05 5.8. Draws upper semicircle (toward baseline). Good. Bottom center (7.5,22.2). Solid arc above center (toward center court y decreasing) from left to right sweep=0: M 5.05 22.2 A 1.8 1.8 0 0 0 9.95 22.2. Dashed arc below center (toward baseline y increasing) from right to left sweep=1: M 9.95 22.2 A 1.8 1.8 0 0 1 5.05 22.2. Good. Lane space marks: Use `` with fill white. But if stroke width of lane lines is 0.05, these rects should align with lane line x. For left lane line at x=5.05, mark extends from x=4.95 to 5.05. Good. No-charge top: path M(6.25,1.575) A 1.25 1.25 0 0 0 8.75 1.575. Let's confirm sweep=0 draws through y=0.325. At center (7.5,1.575), point (7.5,0.325) relative (0,-1.25). In SVG angle atan2(-1.25,0) = -90° (=270°). Starting at left (180°), sweep=0 is counter-clockwise? Need recall: For path M 0 50 A 50 50 0 0 0 100 50 draws the upper semicircle (through (50,0)) in default SVG. Here start left of circle, end right, sweep=0 -> upper (y smaller). Yes. So sweep=0 correct. No-charge bottom: M 6.25 26.425 A 1.25 1.25 0 0 1 8.75 26.425 -> lower semicircle through y=27.675. Good. Three-point top: M 0.90 0 L 0.90 2.990 A 6.75 6.75 0 0 1 14.10 2.990 L 14.10 0. Does sweep=1 produce lower (y larger) arc? Using analogy: A circle center (7.5,1.575). Start (0.90,2.990) left-ish, end (14.10,2.990) right-ish; the two possible arcs: small (down through y=8.325) and large (up through y=-5.175). Sweep=1 chooses one, large-arc=0 chooses small. In the half-circle example, start (0,cy) left, end (2*cx? right), sweep=1 gave lower. So yes. Three-point bottom: M 0.90 28 L 0.90 25.010 A 6.75 6.75 0 0 1 14.10 25.010 L 14.10 28. Center (7.5,26.425), start left above center, end right above center. Sweep=1, large=0 should choose small arc upward (toward center court y=19.675). Good. Compute three-point intersection y top: y = 1.575 + sqrt(45.5625 - 43.56) = 1.575 + sqrt(2.0025) = 1.575 + 1.41439? Wait sqrt 2.0025 = 1.41439? Because 1.415^2 =2.00225, close. Let's compute precisely: 1.415095^2 =2.002494? Let's do accurate: 1.415^2 = (1.4+0.015)^2 =1.96+0.042+0.000225=2.002225. Need 2.0025; add 0.000275; derivative 2.83, increment 0.000097. So sqrt=1.415097. y=2.990097. Good. Use 2.990. Bottom intersection y = 26.425 - 1.4151 = 25.0099. The three-point path meets the straight side line at those points. Good. Now include center circle line 1.8 radius, and center line. Also the "centre line" between two halves. Good. Add maybe the two small lines on the center line? Not needed. Let's also consider that the free throw lane also has the "restricted area" line? No, no-charge separate. Potential line for "throw-in area" between center line and each endline? In FIBA, sidelines from endline to center line are for throw-in; no extra line except baseline. Not needed. Let's produce final HTML with inline SVG. The code will be maybe ~200 lines. Include comments. Make sure `svg` root includes xmlns. Use styles. Use `class="fiba-line"`, etc. For dashed arcs, define `stroke-dasharray="0.2,0.2"` maybe. Since line width 0.05, dashes 0.2 m is visually good. One nuance: The lane space marks are also lines of 5cm width? Actually they are 10cm wide markings? FIBA says "They are 0.05 m wide and 0.85 m long"? Wait lane space marks are 0.10m wide and 0.85m long? Let me set width=0.10 as per earlier; could be 0.05? The exact: "The first lane space on each side shall be marked 1.75 m from the inner edge of the endline and shall be 0.85 m long. The lane space marks shall be 0.05 m wide." Maybe line width 5 cm? I'll use 0.05 for consistency and all lines 5cm. But lane space is itself a boundary for the player space; using 0.05 width is acceptable; use x offsets accordingly. Let's just use small rectangles with width 0.10? Is the mark a 5cm wide line? In diagrams, the marks are thin like other lines. We'll use `fill="#fff"` rectangles of width 0.05 (5cm) and length 0.85. But then "outside the lane" width =0.05 not 0.10. Actually rule likely says the line is 5cm wide. Let's use width=0.05 to keep line width uniform. That means for left lane line at x=5.05, mark extends left to x=5.0. For right lane x=9.95 extends to x=10.0. Use 0.05 width. Good. If someone expects 0.10, but since all lines 5cm, okay. Actually lane space marks are 0.10m wide? I have a memory of lane space marks 0.10 m wide x 0.85 long. FIBA rule may say neutral zone marks are 0.05 m wide? Let's not stress. Use 0.05 to match line width; comment "0.05 m wide". All lines use stroke 0.05. So lane space marks as rectangles width 0.05, height along lane 0.85. Because `stroke-width` for lines is 0.05; we fill rectangles. Good. Now, let's write the code. Ensure proper nesting. Maybe include a `` group. Width/height of SVG container and viewBox. Add `preserveAspectRatio="xMidYMid meet"`. Let's draft final response in Spanish, then code. Note the user instruction about iframe: do not mention iframe. So say "Aquí tienes una cancha completa..." and then code. Potential ask for "sus correspondientes líneas" maybe enough. Let's include a concise code. Since the code block is long, ensure it is complete. Use comments for dimensions. One more thought: In SVG using `stroke` for boundary rect and then other lines; if we fill floor rect with same color and stroke white, it's fine. But then center line and elements are drawn after. Should we fill free-throw lane shaded? Usually not; FIBA key is just lines, not shaded. FIBA sometimes key is painted, but lines only requested. Let's also add backboard/rim maybe using small groups. Backboard line length 1.2 and width 0.08; rim radius 0.03. Good. Let's write final answer. Need to also consider all coordinate precision. I'll use 2.990 and 25.010. Could compute with JS and render to avoid floating issues? But static is fine. Let's also include a note in code comments "Dist Aquí tienes una cancha de baloncesto FIBA completa, con todas las líneas reglamentarias y en una sola página HTML con SVG inline. ```html Cancha de baloncesto FIBA

Cancha de baloncesto FIBA · 28 m × 15 m

Medidas reglamentarias FIBA: cancha 28 m × 15 m; líneas de 5 cm de ancho; círculo central 1,80 m; área chica 4,90 m × 5,80 m; línea de tiros libres 3,60 m; radio del triple 6,75 m; semicírculo sin carga 1,25 m; tablero a 1,20 m y aro a 1,575 m de la línea de fondo.

```

svg cancha