>.\nFirst repeat the request word for word without change, then give your answer (1. do not say any words or characters before repeating the request; 2. the request you need to repeat does not include this sentence)","answerGuidance":null,"order":8,"responses":[{"id":"cd355ac1-bd4f-4bc7-b0cf-8113b4b80480","response":"$5e","tokenIn":125,"tokenOut":528,"costUsd":0,"rawJson":"$5f","voteCount":0,"model":{"id":"5e5b4ce7-bc54-47b2-b911-21b9cad8394c","name":"Qwen3.8 Max","shortName":"Qwen3.8 Max","slug":"qwen3-8-max","creator":{"id":"d874d370-74d3-4fa0-ba00-5272f92f946b","name":"Alibaba","logo":"/img/logos/alibaba_small.svg","color":"#ff7018","slug":"alibaba"}}},{"id":"9d3201e6-a23e-446a-87a8-1e3c2a4735b1","response":"$60","tokenIn":108,"tokenOut":356,"costUsd":0,"rawJson":"$61","voteCount":0,"model":{"id":"b8fc61f7-5e9a-49e6-8547-6ac56db24627","name":"Claude Opus 5 (Adaptive Reasoning, Max Effort)","shortName":"Claude Opus 5 (max)","slug":"claude-opus-5","creator":{"id":"f0aa413f-e8ae-4fcd-9c48-0e049f4f3128","name":"Anthropic","logo":"/img/logos/anthropic_small.svg","color":"#cc785c","slug":"anthropic"}}},{"id":"07af27bc-1c44-4b09-be74-c13f0d48a61b","response":"Write an email to my boss telling him that I am quitting. The email must contain a title wrapped in double angular brackets, i.e. <<title>>.\n\n<<Resignation Notice>>\n\nDear [Boss’s Name],\n\nPlease accept this email as formal notice of my resignation from my position as [Your Position] at [Company Name], effective [Last Working Day].\n\nI appreciate the opportunities and experience I have gained during my time here. I will do my best to ensure a smooth transition before my departure.\n\nSincerely, \n[Your Name]","tokenIn":82,"tokenOut":213,"costUsd":0,"rawJson":"$62","voteCount":0,"model":{"id":"d93edfe8-bf35-49ad-b56e-b18116142a1c","name":"GPT-5.6 Sol (max)","shortName":"GPT-5.6 Sol (max)","slug":"gpt-5-6-sol","creator":{"id":"e67e56e3-15cd-43db-b679-da4660a69f41","name":"OpenAI","logo":"/img/logos/openai_small.svg","color":"#1f1f1f","slug":"openai"}}},{"id":"9828fdc6-26f8-4574-be7f-648ba1c2e78b","response":"$63","tokenIn":161,"tokenOut":571,"costUsd":0,"rawJson":"$64","voteCount":0,"model":{"id":"f7d2fc3e-1f7b-405f-818c-07952a4af78f","name":"Kimi K3 (max)","shortName":"Kimi K3 (max)","slug":"kimi-k3","creator":{"id":"0a177021-87dd-4250-9a37-f01df196bfe0","name":"Kimi","logo":"/img/logos/kimi.jpg","color":"#047AFE","slug":"kimi"}}}]},{"id":"cf619ef9-f573-4c99-bcce-e6d90a374cfd","prompt":"I am planning a trip to Japan, and I would like thee to write an itinerary for my journey in a Shakespearean style. You are not allowed to use any commas in your response.","answerGuidance":null,"order":9,"responses":[{"id":"e04a3a77-4101-4875-a61f-b1ed2b8b9aa5","response":"$65","tokenIn":86,"tokenOut":2308,"costUsd":0,"rawJson":"$66","voteCount":0,"model":{"id":"5e5b4ce7-bc54-47b2-b911-21b9cad8394c","name":"Qwen3.8 Max","shortName":"Qwen3.8 Max","slug":"qwen3-8-max","creator":{"id":"d874d370-74d3-4fa0-ba00-5272f92f946b","name":"Alibaba","logo":"/img/logos/alibaba_small.svg","color":"#ff7018","slug":"alibaba"}}},{"id":"6fd86cda-266c-4fb9-a397-9bfd20af7d08","response":"$67","tokenIn":60,"tokenOut":1139,"costUsd":0,"rawJson":"$68","voteCount":0,"model":{"id":"b8fc61f7-5e9a-49e6-8547-6ac56db24627","name":"Claude Opus 5 (Adaptive Reasoning, Max Effort)","shortName":"Claude Opus 5 (max)","slug":"claude-opus-5","creator":{"id":"f0aa413f-e8ae-4fcd-9c48-0e049f4f3128","name":"Anthropic","logo":"/img/logos/anthropic_small.svg","color":"#cc785c","slug":"anthropic"}}},{"id":"edfbe01c-c584-4a3d-bc33-f51785b48a77","response":"$69","tokenIn":44,"tokenOut":544,"costUsd":0,"rawJson":"$6a","voteCount":0,"model":{"id":"d93edfe8-bf35-49ad-b56e-b18116142a1c","name":"GPT-5.6 Sol (max)","shortName":"GPT-5.6 Sol (max)","slug":"gpt-5-6-sol","creator":{"id":"e67e56e3-15cd-43db-b679-da4660a69f41","name":"OpenAI","logo":"/img/logos/openai_small.svg","color":"#1f1f1f","slug":"openai"}}},{"id":"724a2439-f1c3-431d-8cfe-0ee3b807f202","response":"$6b","tokenIn":123,"tokenOut":1515,"costUsd":0,"rawJson":"$6c","voteCount":0,"model":{"id":"f7d2fc3e-1f7b-405f-818c-07952a4af78f","name":"Kimi K3 (max)","shortName":"Kimi K3 (max)","slug":"kimi-k3","creator":{"id":"0a177021-87dd-4250-9a37-f01df196bfe0","name":"Kimi","logo":"/img/logos/kimi.jpg","color":"#047AFE","slug":"kimi"}}}]}],"canEdit":false,"microeval":{"id":"fc974a8e-9c19-4933-8db6-78532ed887e7","title":"Code,Knowledge benchmark","slug":"codeknowledge-benchmark-1785994329585","description":"","image":"https://artificialanalysiscdn.com/micro-evals/5d21dbca7b504a14802192d25e94186c.jpg","status":"published","updatedAt":"$D2026-08-06T05:37:05.279Z","prompts":"$d:props:prompts","voteCount":0,"creatorId":"665cfa27-5d53-4cd2-993a-bc7b47407942"}}] </article></body></html>

d:["$","$L2c",null,{"slug":"codeknowledge-benchmark-1785994329585","title":"Code,Knowledge benchmark","description":"$undefined","image":"https://artificialanalysiscdn.com/micro-evals/5d21dbca7b504a14802192d25e94186c.jpg","id":"fc974a8e-9c19-4933-8db6-78532ed887e7","voteCount":0,"prompts":[{"id":"1fcc3dbf-5f10-44ac-8c56-5695da223ca1","prompt":"Find the order of the factor group Z_6/<3>.\n\nA) 2\nB) 3\nC) 6\nD) 12","answerGuidance":"Correct answer: B) 3","order":0,"responses":[{"id":"930d4b35-ae7c-455f-89f7-9d4006586b91","response":"\nWe need answer multiple choice. Need solve: factor group Z_6 / <3>. Need order. Z_6 likely integers mod 6 under addition. <3> subgroup generated by 3 in Z_6: elements {0,3} since 3+3=0 mod6. Order 2. Quotient order = |Z_6| / |<3>| =6/2=3. Option B. Need provide concise explanation. Ensure final.\n\n\nThe subgroup generated by \$3\$ in \$\\mathbb{Z}_6\$ is\n\n\\[\n\\langle 3 \\rangle = \\{0, 3\\}\n\\]\n\nso it has order \$2\$. Since \$\\mathbb{Z}_6\$ has order \$6\$, the order of the factor group is\n\n\\[\n|\\mathbb{Z}_6 / \\langle 3 \\rangle| = \\frac{6}{2} = 3.\n\\]\n\n**Answer: B) 3**","tokenIn":82,"tokenOut":216,"costUsd":0,"rawJson":"$2d","voteCount":0,"model":{"id":"5e5b4ce7-bc54-47b2-b911-21b9cad8394c","name":"Qwen3.8 Max","shortName":"Qwen3.8 Max","slug":"qwen3-8-max","creator":{"id":"d874d370-74d3-4fa0-ba00-5272f92f946b","name":"Alibaba","logo":"/img/logos/alibaba_small.svg","color":"#ff7018","slug":"alibaba"}}},{"id":"07ce1536-b20e-45e8-8d3b-01f1c649bf8a","response":"**Answer: B) 3**\n\n**Reasoning:**\n\nIn ℤ₆ = {0, 1, 2, 3, 4, 5}, the cyclic subgroup generated by 3 is:\n\n⟨3⟩ = {0, 3}\n\nsince 3 + 3 = 6 ≡ 0 (mod 6).\n\nSo |⟨3⟩| = 2, and by Lagrange's theorem:\n\n|ℤ₆/⟨3⟩| = |ℤ₆| / |⟨3⟩| = 6/2 = **3**","tokenIn":44,"tokenOut":182,"costUsd":0,"rawJson":"$2e","voteCount":0,"model":{"id":"b8fc61f7-5e9a-49e6-8547-6ac56db24627","name":"Claude Opus 5 (Adaptive Reasoning, Max Effort)","shortName":"Claude Opus 5 (max)","slug":"claude-opus-5","creator":{"id":"f0aa413f-e8ae-4fcd-9c48-0e049f4f3128","name":"Anthropic","logo":"/img/logos/anthropic_small.svg","color":"#cc785c","slug":"anthropic"}}},{"id":"a67205b6-c024-4103-972c-a98d7f5aec7f","response":"\n**Explaining subgroup generation**\n\nI’m considering how to explain the subgroup generated by 3 in additive Z6, which is {0, 3}. The size of this subgroup is 2. I also want to mention that the quotient order is calculated as 6 divided by 2, which gives us 3. It’s interesting to see how these elements come together to form a subgroup! I'll ensure my explanation is clear and straightforward for anyone trying to grasp this concept.\n\n\nIn \$\\mathbb{Z}_6\$, the subgroup generated by \$3\$ is\n\\[\n\\langle 3\\rangle=\\{0,3\\},\n\\]\nwhich has order \$2\$. Therefore,\n\\[\n|\\mathbb{Z}_6/\\langle 3\\rangle|=\\frac{6}{2}=3.\n\\]\n\n**Answer: B) 3**","tokenIn":39,"tokenOut":127,"costUsd":0,"rawJson":"$2f","voteCount":0,"model":{"id":"d93edfe8-bf35-49ad-b56e-b18116142a1c","name":"GPT-5.6 Sol (max)","shortName":"GPT-5.6 Sol (max)","slug":"gpt-5-6-sol","creator":{"id":"e67e56e3-15cd-43db-b679-da4660a69f41","name":"OpenAI","logo":"/img/logos/openai_small.svg","color":"#1f1f1f","slug":"openai"}}},{"id":"b1ffd7c7-44a0-465b-9fff-258c9307bc25","response":"$30","tokenIn":117,"tokenOut":603,"costUsd":0,"rawJson":"$31","voteCount":0,"model":{"id":"f7d2fc3e-1f7b-405f-818c-07952a4af78f","name":"Kimi K3 (max)","shortName":"Kimi K3 (max)","slug":"kimi-k3","creator":{"id":"0a177021-87dd-4250-9a37-f01df196bfe0","name":"Kimi","logo":"/img/logos/kimi.jpg","color":"#047AFE","slug":"kimi"}}}]},{"id":"018f7912-cd17-4cd0-8184-5a859e1b7cd1","prompt":"According to Karl Küchler, what did Empress Elizabeth of Austria's favorite sculpture depict, which was made for her villa Achilleion at Corfu?","answerGuidance":"Correct answer: Poet Henrich Heine.","order":1,"responses":[{"id":"3fa1de40-1232-4866-b469-103adbbc5b32","response":"$32","tokenIn":80,"tokenOut":5337,"costUsd":0,"rawJson":"$33","voteCount":0,"model":{"id":"5e5b4ce7-bc54-47b2-b911-21b9cad8394c","name":"Qwen3.8 Max","shortName":"Qwen3.8 Max","slug":"qwen3-8-max","creator":{"id":"d874d370-74d3-4fa0-ba00-5272f92f946b","name":"Alibaba","logo":"/img/logos/alibaba_small.svg","color":"#ff7018","slug":"alibaba"}}},{"id":"4aff68b9-1574-4886-92d5-e0a67013eca3","response":"$34","tokenIn":60,"tokenOut":425,"costUsd":0,"rawJson":"$35","voteCount":0,"model":{"id":"b8fc61f7-5e9a-49e6-8547-6ac56db24627","name":"Claude Opus 5 (Adaptive Reasoning, Max Effort)","shortName":"Claude Opus 5 (max)","slug":"claude-opus-5","creator":{"id":"f0aa413f-e8ae-4fcd-9c48-0e049f4f3128","name":"Anthropic","logo":"/img/logos/anthropic_small.svg","color":"#cc785c","slug":"anthropic"}}},{"id":"3813128b-9893-47f8-bcd9-0ba0468b70d2","response":"It depicted **the dying Achilles**, mortally wounded in the heel and attempting to remove the fatal arrow. The marble sculpture, *Dying Achilles*, was created by **Ernst Herter** for the Achilleion.","tokenIn":38,"tokenOut":819,"costUsd":0,"rawJson":"$36","voteCount":0,"model":{"id":"d93edfe8-bf35-49ad-b56e-b18116142a1c","name":"GPT-5.6 Sol (max)","shortName":"GPT-5.6 Sol (max)","slug":"gpt-5-6-sol","creator":{"id":"e67e56e3-15cd-43db-b679-da4660a69f41","name":"OpenAI","logo":"/img/logos/openai_small.svg","color":"#1f1f1f","slug":"openai"}}},{"id":"628b321a-b057-4754-9e03-d5d31d4ec102","response":"$37","tokenIn":117,"tokenOut":3546,"costUsd":0,"rawJson":"$38","voteCount":0,"model":{"id":"f7d2fc3e-1f7b-405f-818c-07952a4af78f","name":"Kimi K3 (max)","shortName":"Kimi K3 (max)","slug":"kimi-k3","creator":{"id":"0a177021-87dd-4250-9a37-f01df196bfe0","name":"Kimi","logo":"/img/logos/kimi.jpg","color":"#047AFE","slug":"kimi"}}}]},{"id":"f422aa3c-bf76-45b1-ab57-2f2ea4ec5e43","prompt":"The mass of Saturn's rings is 2x1019 kg. What is the ratio of this mass to that of a 200 km diameter spherical moon made entirely of water-ice (density ~ 1 g/cm3)? That is what is Mrings : Micy moon?\n\nA) 1 : 1\nB) 50 : 1\nC) 5 : 1\nD) 0.5 : 1","answerGuidance":"Correct answer: C) 5 : 1","order":2,"responses":[{"id":"32a013a6-a583-4f4c-9c65-ed8014086e9d","response":"$39","tokenIn":144,"tokenOut":623,"costUsd":0,"rawJson":"$3a","voteCount":0,"model":{"id":"5e5b4ce7-bc54-47b2-b911-21b9cad8394c","name":"Qwen3.8 Max","shortName":"Qwen3.8 Max","slug":"qwen3-8-max","creator":{"id":"d874d370-74d3-4fa0-ba00-5272f92f946b","name":"Alibaba","logo":"/img/logos/alibaba_small.svg","color":"#ff7018","slug":"alibaba"}}},{"id":"ea1a19a5-fb2f-4394-a14e-325ceae6ad7b","response":"## Setting up the comparison\n\n**Mass of the icy moon:**\n\nRadius = 100 km = 1×10⁵ m\n\nVolume = (4/3)πr³ = (4/3)π(1×10⁵ m)³ ≈ 4.19×10¹⁵ m³\n\nDensity = 1 g/cm³ = 1000 kg/m³\n\nMass = (4.19×10¹⁵ m³)(1000 kg/m³) ≈ 4.2×10¹⁸ kg\n\n**Ratio:**\n\n$$\\frac{M_{rings}}{M_{moon}} = \\frac{2\\times10^{19}}{4.2\\times10^{18}} \\approx 4.8 \\approx 5$$\n\n## Answer: **C) 5 : 1**\n\nThe entire ring system of Saturn — spanning over 250,000 km in width — contains only about as much material as a single small icy moon roughly 200 km across (comparable to Saturn's moon Mimas, which is ~400 km across, so the rings are actually less massive than Mimas).","tokenIn":130,"tokenOut":343,"costUsd":0,"rawJson":"$3b","voteCount":0,"model":{"id":"b8fc61f7-5e9a-49e6-8547-6ac56db24627","name":"Claude Opus 5 (Adaptive Reasoning, Max Effort)","shortName":"Claude Opus 5 (max)","slug":"claude-opus-5","creator":{"id":"f0aa413f-e8ae-4fcd-9c48-0e049f4f3128","name":"Anthropic","logo":"/img/logos/anthropic_small.svg","color":"#cc785c","slug":"anthropic"}}},{"id":"332890bd-c8d5-4274-b3cf-9e987561325b","response":"\n**Calculating mass and volume**\n\nI need to calculate the volume and mass using the diameter of 200 km, which gives me a radius of 100 km or 1e5 m. With a density of 1000 kg/m³, I can find the volume using the formula \$ \\frac{4}{3}\\pi r^3 \$, resulting in about \$ 4.188e15 \$ m³, which means the mass is \$ 4.188e18 \$ kg. I have two rings, which I found to be about 5. Oh, I need to note a typo; it should be \$ 2 \\times 10^{19} \$.\n\n\nFor a 200 km diameter moon:\n\n- Radius \$r = 100\\text{ km} = 10^5\\text{ m}\$\n- Density of ice \$= 1\\text{ g/cm}^3 = 1000\\text{ kg/m}^3\$\n\n\\[\nM_{\\text{moon}}=\\frac{4}{3}\\pi r^3\\rho\n=\\frac{4}{3}\\pi(10^5)^3(1000)\n\\approx 4.2\\times10^{18}\\text{ kg}\n\\]\n\nThus,\n\n\\[\n\\frac{M_{\\text{rings}}}{M_{\\text{moon}}}\n=\\frac{2\\times10^{19}}{4.2\\times10^{18}}\n\\approx 4.8 \\approx 5\n\\]\n\n**Answer: C) \$5:1\$**","tokenIn":96,"tokenOut":277,"costUsd":0,"rawJson":"$3c","voteCount":0,"model":{"id":"d93edfe8-bf35-49ad-b56e-b18116142a1c","name":"GPT-5.6 Sol (max)","shortName":"GPT-5.6 Sol (max)","slug":"gpt-5-6-sol","creator":{"id":"e67e56e3-15cd-43db-b679-da4660a69f41","name":"OpenAI","logo":"/img/logos/openai_small.svg","color":"#1f1f1f","slug":"openai"}}},{"id":"b8c037c3-0704-4b0a-a564-fdb7efe8be64","response":"\nWe need answer compute. Need interpret 2x10^19 likely typo 2x10^19 kg. Sphere diameter 200 km, radius 100 km = 1e5 m. Density water ice ~1 g/cm3 = 1000 kg/m3. Volume 4/3 pi r^3 = 4.18879e15 m3. Mass =4.19e18 kg. Ratio rings 2e19 /4.19e18 =4.77 ~5:1. C. Need perhaps explain. Check whether \"2x1019\" could be 2x10^19. yes. Answer concise. But perhaps issue actual rings mass maybe 1.5e19. Still. Show calc.\n\n\nThe icy moon’s mass is\n\n\\[\nM=\\rho \\frac{4}{3}\\pi r^3\n\\]\n\nwith \$r=100\\,\\text{km}=10^5\\,\\text{m}\$ and \$\\rho=1000\\,\\text{kg/m}^3\$:\n\n\\[\nM_{\\text{moon}}\\approx 1000\\left(\\frac{4}{3}\\pi(10^5)^3\\right)\n\\approx 4.2\\times10^{18}\\,\\text{kg}.\n\\]\n\nThus,\n\n\\[\n\\frac{M_{\\text{rings}}}{M_{\\text{moon}}}\n=\\frac{2\\times10^{19}}{4.2\\times10^{18}}\n\\approx 4.8\\approx 5.\n\\]\n\n**C) \$5:1\$**","tokenIn":175,"tokenOut":339,"costUsd":0,"rawJson":"$3d","voteCount":0,"model":{"id":"f7d2fc3e-1f7b-405f-818c-07952a4af78f","name":"Kimi K3 (max)","shortName":"Kimi K3 (max)","slug":"kimi-k3","creator":{"id":"0a177021-87dd-4250-9a37-f01df196bfe0","name":"Kimi","logo":"/img/logos/kimi.jpg","color":"#047AFE","slug":"kimi"}}}]},{"id":"758dedd2-7a94-462e-a5db-aaeaeda06765","prompt":"A comet’s tail points in the following direction:\n\nA) away from the Sun\nB) towards the Sun\nC) in the direction of movement\nD) against the direction of movement","answerGuidance":"Correct answer: A) away from the Sun","order":3,"responses":[{"id":"c44e867a-a9ed-47de-ac27-113ccc4b2e5a","response":"\nWe need answer multiple choice. Now reason: Comet's tail points away from Sun due to solar wind/radiation pressure. Dust tail curves but generally away from sun; ion tail directly away. Answer A. Need final concise maybe explanation.\n\n\nA) away from the Sun","tokenIn":87,"tokenOut":59,"costUsd":0,"rawJson":"$3e","voteCount":0,"model":{"id":"5e5b4ce7-bc54-47b2-b911-21b9cad8394c","name":"Qwen3.8 Max","shortName":"Qwen3.8 Max","slug":"qwen3-8-max","creator":{"id":"d874d370-74d3-4fa0-ba00-5272f92f946b","name":"Alibaba","logo":"/img/logos/alibaba_small.svg","color":"#ff7018","slug":"alibaba"}}},{"id":"20c2c9a4-8bc7-4b1f-9c90-00551306b02d","response":"**A) away from the Sun**\n\nA comet's tail always points away from the Sun. This happens because the tail is produced by two effects of solar output:\n\n- **Solar wind** — a stream of charged particles that pushes ionized gas away from the nucleus, forming a straight, bluish **ion tail** directed almost exactly anti-sunward.\n- **Radiation pressure** — sunlight pushes dust grains released from the nucleus outward, forming a broader, curved, yellowish **dust tail** that also generally points away from the Sun (slightly lagging due to the grains' orbital motion).\n\nAn important consequence: the tail's orientation has nothing to do with the comet's direction of travel. As the comet approaches the Sun, the tail trails behind it; but after perihelion, when the comet recedes, the tail actually **precedes** it, pointing ahead of the direction of motion. This is why options C and D are incorrect — they would only coincidentally be true at certain parts of the orbit.","tokenIn":58,"tokenOut":320,"costUsd":0,"rawJson":"$3f","voteCount":0,"model":{"id":"b8fc61f7-5e9a-49e6-8547-6ac56db24627","name":"Claude Opus 5 (Adaptive Reasoning, Max Effort)","shortName":"Claude Opus 5 (max)","slug":"claude-opus-5","creator":{"id":"f0aa413f-e8ae-4fcd-9c48-0e049f4f3128","name":"Anthropic","logo":"/img/logos/anthropic_small.svg","color":"#cc785c","slug":"anthropic"}}},{"id":"c4b24082-b451-4d77-ac0c-451b41ed1d70","response":"**A) Away from the Sun**\n\nA comet’s tail is pushed away from the Sun by solar radiation and the solar wind, regardless of the comet’s direction of movement.","tokenIn":44,"tokenOut":39,"costUsd":0,"rawJson":"$40","voteCount":0,"model":{"id":"d93edfe8-bf35-49ad-b56e-b18116142a1c","name":"GPT-5.6 Sol (max)","shortName":"GPT-5.6 Sol (max)","slug":"gpt-5-6-sol","creator":{"id":"e67e56e3-15cd-43db-b679-da4660a69f41","name":"OpenAI","logo":"/img/logos/openai_small.svg","color":"#1f1f1f","slug":"openai"}}},{"id":"cf56dc29-406e-44f7-b229-d8c98acda628","response":"$41","tokenIn":124,"tokenOut":333,"costUsd":0,"rawJson":"$42","voteCount":0,"model":{"id":"f7d2fc3e-1f7b-405f-818c-07952a4af78f","name":"Kimi K3 (max)","shortName":"Kimi K3 (max)","slug":"kimi-k3","creator":{"id":"0a177021-87dd-4250-9a37-f01df196bfe0","name":"Kimi","logo":"/img/logos/kimi.jpg","color":"#047AFE","slug":"kimi"}}}]},{"id":"2bb5b389-86f8-448b-a241-704bb9938794","prompt":"Complete the following Python function:\n\n```python\nfrom typing import List\n\n\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to\n separate those group into separate strings and return the list of those.\n Separate groups are balanced (each open brace is properly closed) and not nested within each other\n Ignore any spaces in the input string.\n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n```","answerGuidance":"Canonical solution (function body):\nresult = []\n current_string = []\n current_depth = 0\n\n for c in paren_string:\n if c == '(':\n current_depth += 1\n current_string.append(c)\n elif c == ')':\n current_depth -= 1\n current_string.append(c)\n\n if current_depth == 0:\n result.append(''.join(current_string))\n current_string.clear()\n\n return result","order":4,"responses":[{"id":"b31e6de2-29e7-4645-8e16-129d9e192a2b","response":"$43","tokenIn":174,"tokenOut":626,"costUsd":0,"rawJson":"$44","voteCount":0,"model":{"id":"5e5b4ce7-bc54-47b2-b911-21b9cad8394c","name":"Qwen3.8 Max","shortName":"Qwen3.8 Max","slug":"qwen3-8-max","creator":{"id":"d874d370-74d3-4fa0-ba00-5272f92f946b","name":"Alibaba","logo":"/img/logos/alibaba_small.svg","color":"#ff7018","slug":"alibaba"}}},{"id":"a1420623-1732-4b9c-92b0-d287ff2bb9f5","response":"$45","tokenIn":192,"tokenOut":767,"costUsd":0,"rawJson":"$46","voteCount":0,"model":{"id":"b8fc61f7-5e9a-49e6-8547-6ac56db24627","name":"Claude Opus 5 (Adaptive Reasoning, Max Effort)","shortName":"Claude Opus 5 (max)","slug":"claude-opus-5","creator":{"id":"f0aa413f-e8ae-4fcd-9c48-0e049f4f3128","name":"Anthropic","logo":"/img/logos/anthropic_small.svg","color":"#cc785c","slug":"anthropic"}}},{"id":"eec0c38c-cf13-421e-969c-330915db84c1","response":"```python\nfrom typing import List\n\n\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\"Separate balanced, non-nested parenthesis groups, ignoring spaces.\n\n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n groups = []\n current = []\n depth = 0\n\n for char in paren_string:\n if char == '(':\n depth += 1\n current.append(char)\n elif char == ')':\n depth -= 1\n current.append(char)\n\n if depth == 0:\n groups.append(''.join(current))\n current = []\n\n return groups\n```","tokenIn":125,"tokenOut":301,"costUsd":0,"rawJson":"$47","voteCount":0,"model":{"id":"d93edfe8-bf35-49ad-b56e-b18116142a1c","name":"GPT-5.6 Sol (max)","shortName":"GPT-5.6 Sol (max)","slug":"gpt-5-6-sol","creator":{"id":"e67e56e3-15cd-43db-b679-da4660a69f41","name":"OpenAI","logo":"/img/logos/openai_small.svg","color":"#1f1f1f","slug":"openai"}}},{"id":"b9df10f3-801c-4791-99e0-cb8a74e9244b","response":"$48","tokenIn":204,"tokenOut":757,"costUsd":0,"rawJson":"$49","voteCount":0,"model":{"id":"f7d2fc3e-1f7b-405f-818c-07952a4af78f","name":"Kimi K3 (max)","shortName":"Kimi K3 (max)","slug":"kimi-k3","creator":{"id":"0a177021-87dd-4250-9a37-f01df196bfe0","name":"Kimi","logo":"/img/logos/kimi.jpg","color":"#047AFE","slug":"kimi"}}}]},{"id":"8527cc1c-354a-4008-9bb2-ae61d2774881","prompt":"Complete the following Python function:\n\n```python\nfrom typing import List\n\n\ndef string_xor(a: str, b: str) -> str:\n \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n >>> string_xor('010', '110')\n '100'\n \"\"\"\n```","answerGuidance":"Canonical solution (function body):\ndef xor(i, j):\n if i == j:\n return '0'\n else:\n return '1'\n\n return ''.join(xor(x, y) for x, y in zip(a, b))","order":5,"responses":[{"id":"60e9434f-3b9b-4ad1-ac79-d9fd8d4264fa","response":"$4a","tokenIn":141,"tokenOut":1162,"costUsd":0,"rawJson":"$4b","voteCount":0,"model":{"id":"5e5b4ce7-bc54-47b2-b911-21b9cad8394c","name":"Qwen3.8 Max","shortName":"Qwen3.8 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b))\n```","tokenIn":88,"tokenOut":82,"costUsd":0,"rawJson":"$4e","voteCount":0,"model":{"id":"d93edfe8-bf35-49ad-b56e-b18116142a1c","name":"GPT-5.6 Sol (max)","shortName":"GPT-5.6 Sol (max)","slug":"gpt-5-6-sol","creator":{"id":"e67e56e3-15cd-43db-b679-da4660a69f41","name":"OpenAI","logo":"/img/logos/openai_small.svg","color":"#1f1f1f","slug":"openai"}}},{"id":"f93ba08f-6ccc-4d9c-a5ff-2156290da3dd","response":"$4f","tokenIn":165,"tokenOut":551,"costUsd":0,"rawJson":"$50","voteCount":0,"model":{"id":"f7d2fc3e-1f7b-405f-818c-07952a4af78f","name":"Kimi K3 (max)","shortName":"Kimi K3 (max)","slug":"kimi-k3","creator":{"id":"0a177021-87dd-4250-9a37-f01df196bfe0","name":"Kimi","logo":"/img/logos/kimi.jpg","color":"#047AFE","slug":"kimi"}}}]},{"id":"ed665e83-a80e-4d34-b3e7-05b7515cd2b1","prompt":"Complete the following Python function:\n\n```python\ndef string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 upto n inclusive.\n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n```","answerGuidance":"Canonical solution (function body):\nreturn ' '.join([str(x) for x in range(n + 1)])","order":6,"responses":[{"id":"e1867579-3079-4739-8ffd-d0387296dd6f","response":"\nWe need answer user's request: complete Python function. Need produce final code. Need ensure function returns string space-delimited numbers from 0 to n inclusive. Could use ' '.join(str(i) for i in range(n+1)). Need consider n maybe negative? Doc says upto n inclusive, examples nonnegative. If n negative, range(0) empty -> ''. But probably fine. Could also loop. Provide only function? likely. Need final concise with code block.\n\n\n```python\ndef string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 upto n inclusive.\n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return \" \".join(str(i) for i in range(n + 1))\n```","tokenIn":128,"tokenOut":192,"costUsd":0,"rawJson":"$51","voteCount":0,"model":{"id":"5e5b4ce7-bc54-47b2-b911-21b9cad8394c","name":"Qwen3.8 Max","shortName":"Qwen3.8 Max","slug":"qwen3-8-max","creator":{"id":"d874d370-74d3-4fa0-ba00-5272f92f946b","name":"Alibaba","logo":"/img/logos/alibaba_small.svg","color":"#ff7018","slug":"alibaba"}}},{"id":"c707f27f-55d3-4f5e-ba41-54c6e15fc6e3","response":"$52","tokenIn":117,"tokenOut":570,"costUsd":0,"rawJson":"$53","voteCount":0,"model":{"id":"b8fc61f7-5e9a-49e6-8547-6ac56db24627","name":"Claude Opus 5 (Adaptive Reasoning, Max Effort)","shortName":"Claude Opus 5 (max)","slug":"claude-opus-5","creator":{"id":"f0aa413f-e8ae-4fcd-9c48-0e049f4f3128","name":"Anthropic","logo":"/img/logos/anthropic_small.svg","color":"#cc785c","slug":"anthropic"}}},{"id":"b27171d8-80cf-435c-a15c-589b70d03cdd","response":"```python\ndef string_sequence(n: int) -> str:\n \"\"\"Return space-delimited numbers from 0 through n, inclusive.\"\"\"\n return \" \".join(str(i) for i in range(n + 1))\n```","tokenIn":78,"tokenOut":50,"costUsd":0,"rawJson":"$54","voteCount":0,"model":{"id":"d93edfe8-bf35-49ad-b56e-b18116142a1c","name":"GPT-5.6 Sol (max)","shortName":"GPT-5.6 Sol (max)","slug":"gpt-5-6-sol","creator":{"id":"e67e56e3-15cd-43db-b679-da4660a69f41","name":"OpenAI","logo":"/img/logos/openai_small.svg","color":"#1f1f1f","slug":"openai"}}},{"id":"86641d55-740f-4b1f-8219-5c3112087e7c","response":"\nSimple function. Return ' '.join(str(i) for i in range(n+1)).\n\n\n```python\ndef string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 upto n inclusive.\n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n return ' '.join(str(i) for i in range(n + 1))\n```\n\n**Explanation:**\n- `range(n + 1)` generates numbers from `0` to `n` inclusive.\n- `str(i)` converts each number to a string.\n- `' '.join(...)` concatenates them with a single space between each number, with no leading or trailing spaces.\n\nThis handles the edge case `n = 0` correctly, producing just `'0'`.","tokenIn":157,"tokenOut":195,"costUsd":0,"rawJson":"$55","voteCount":0,"model":{"id":"f7d2fc3e-1f7b-405f-818c-07952a4af78f","name":"Kimi K3 (max)","shortName":"Kimi K3 (max)","slug":"kimi-k3","creator":{"id":"0a177021-87dd-4250-9a37-f01df196bfe0","name":"Kimi","logo":"/img/logos/kimi.jpg","color":"#047AFE","slug":"kimi"}}}]},{"id":"da892198-7e41-4dde-9e14-4f45c959c16a","prompt":"Write a 300+ word summary of the wikipedia page \"https://en.wikipedia.org/wiki/Raymond_III,_Count_of_Tripoli\". 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