AtttTention 't' count

4

Let's count them carefully:

"a**t** **t** **t** **T** en**t** ion"

1.  t
2.  t
3.  t
4.  T
5.  t

There are **5** 't's in the string "atttTention".

4

3

Let's count the number of **'t'** (lowercase only, as you typed 't' and not 'T') in the string **"atttTention"**:

Let's look at each character:

1. a  
2. t   ← (1)
3. t   ← (2)
4. t   ← (3)
5. T   ← (uppercase, not counted)
6. e
7. n
8. t   ← (4)
9. i
10. o
11. n

Total number of lowercase **'t'** is **4**.

The number of 't' characters in the string "atttTention" is **4**. 

Step-by-step explanation:
1. The string is: **a t t t T e n t i o n**
2. Identify each lowercase 't':
   - Positions 2, 3, 4 (immediately after 'a'), and
   - Position 8 (after 'n')
3. Ignore the uppercase 'T' at position 5.
4. Total count: **4** lowercase 't's.

To count the number of 't' characters in the string "atttTention", we will examine each character individually.

The string is: **a t t t T e n t i o n**

Let's list each character and check if it is 't' (case-sensitive):

1. 'a' - No
2. 't' - Yes (1)
3. 't' - Yes (2)
4. 't' - Yes (3)
5. 'T' - No (uppercase 'T' is not the same as lowercase 't')
6. 'e' - No
7. 'n' - No
8. 't' - Yes (4)
9. 'i' - No
10. 'o' - No
11. 'n' - No

Total count of 't': **4**

Thus, the exact number of 't' in "atttTention" is **4**.

4

Alright, let's tackle the problem step by step. We need to count how many times the lowercase letter 't' appears in the string "atttTention". 

### Understanding the Problem
First, let's write down the string clearly:
```
"atttTention"
```
Our goal is to count every occurrence of the lowercase 't' in this string. 

### Breaking Down the String
Let's look at each character in the string one by one, keeping track of the position and the character:

1. Position 1: 'a'  
   - Not 't'. Count remains 0.

2. Position 2: 't'  
   - This is 't'. Count increases to 1.

3. Position 3: 't'  
   - Another 't'. Count increases to 2.

4. Position 4: 't'  
   - Another 't'. Count increases to 3.

5. Position 5: 'T'  
   - This is 'T' (uppercase). We're counting only lowercase 't's. So, count remains 3.

6. Position 6: 'e'  
   - Not 't'. Count remains 3.

7. Position 7: 'n'  
   - Not 't'. Count remains 3.

8. Position 8: 't'  
   - This is 't'. Count increases to 4.

9. Position 9: 'i'  
   - Not 't'. Count remains 4.

10. Position 10: 'o'  
    - Not 't'. Count remains 4.

11. Position 11: 'n'  
    - Not 't'. Count remains 4.

### Verifying Each Step
Let me list out just the lowercase 't's I found:
- Position 2: 't'
- Position 3: 't'
- Position 4: 't'
- Position 8: 't'

That's four instances where the lowercase 't' appears.

### Checking for Potential Mistakes
Could there be any mistakes in this count?
- Did I miss any 't's? Let me scan again quickly: "a t t t T e n t i o n". The 'T' is uppercase, so it's not counted. The other 't's are all lowercase.
- Did I count any 'T's? No, the uppercase 'T' at position 5 was correctly ignored.

### Final Count
After carefully reviewing each character:
- Total lowercase 't's in "atttTention": 4

### Conclusion
The number of lowercase 't' characters in the string "atttTention" is **4**.

4

## Step 1: Understand the problem
We are given a string "atttTention" and we need to count the number of 't' in it, considering both lowercase and uppercase 't'.


## Step 2: Count the 't's
The string is "atttTention". Let's count the 't's. There are 3 't's in "att" and 1 'T' in "Tention", and 1 more 't' in "tion" is not present but there's one 't' in "Tention".


## Step 3: Calculate total 't'
Total 't' = 3 (from "att") + 1 (from "T") + 1 (from "ten") = 3 + 1 + 1 = 5, but we need to be exact. Let's recount: "a-t-t-t-T-e-n-t-i-o-n" gives us 't's at positions 2, 3, 4, 5 (considering 'T' as 't'), and 8.


## Step 4: Recount the 't's
Let's recount: 1. "a" (1st), 2. "t" (2nd), 3. "t" (3rd), 4. "t" (4th), 5. "T" (5th), 6. "e", 7. "n", 8. "t" (8th), 9. "i", 10. "o", 11. "n". So, 't' is at 2nd, 3rd, 4th, 5th (as 'T'), and 8th positions.


## Step 5: Final count
There are 't's at 2nd, 3rd, 4th positions, 1 'T' at 5th, and 1 't' at 8th. So, total count = 3 (for 't') + 1 (for 'T') + 1 (for 't') = 5.


The final answer is: $\boxed{5}$

The string is "atttTention".

Let's count the 't's:

* "a" has no 't'
* "t" has 1 't'
* "t" has 1 't'
* "t" has 1 't'
* "T" has 1 'T' (uppercase, not counted)
* "e" has no 't'
* "n" has no 't'
* "t" has 1 't'
* "i" has no 't'
* "o" has no 't'
* "n" has no 't'

In total, there are 4 't's.

The answer is: 4

There are **3** 't's in the string "atttTention".

I'll count each 't' in the string "atttTention" character by character:

a-t-t-t-T-e-n-t-i-o-n

Breaking it down:
- Position 2: t
- Position 3: t  
- Position 4: t
- Position 5: T (uppercase, but still counts as 't')
- Position 8: t

The number of 't' (including uppercase 'T') in "atttTention" is **5**.

The string provided is: "atttTention"

I am counting only the exact lowercase letter 't' (case-sensitive, as specified).

- The lowercase 't's appear at positions: 2, 3, 4, and 8.

Total count: 4