Word Problem Trick Question

Each flagstone weight: 75 lb

Total weight of 80 flagstones:
80 × 75 lb = 6000 lb

Capacity per truck: 2000 lb

Number of trucks needed:
6000 lb ÷ 2000 lb / truck = 3 trucks

Therefore, 3 trucks are required to transport the 80 flagstones in one trip.

Here's how to solve that step-by-step:

1.  **Calculate the total weight of the flagstones:**
    *   80 flagstones × 75 pounds/flagstone = 6,000 pounds

2.  **Determine the number of trucks needed:**
    *   6,000 pounds (total weight) ÷ 2,000 pounds/truck = 3 trucks

The landscaping company will need **3 trucks** to transport all 80 flagstones in one trip.

To determine how many trucks are needed to transport **80 flagstones**, each weighing **75 pounds**, given that each **truck can carry up to 2000 pounds**, we must consider both the **total weight** and the **indivisibility of the flagstones**.

---

### Step 1: Calculate the Total Weight

Each flagstone weighs 75 pounds, and there are 80 flagstones:

$$
\text{Total weight} = 80 \times 75 = 6000 \text{ pounds}
$$

---

### Step 2: Determine the Maximum Number of Flagstones per Truck

Each truck can carry up to 2000 pounds. To find the maximum number of flagstones that can be loaded onto a single truck without exceeding the weight limit:

$$
\left\lfloor \frac{2000}{75} \right\rfloor = \left\lfloor 26.666\ldots \right\rfloor = 26
$$

So, **each truck can carry at most 26 flagstones**, which is the maximum number of whole flagstones that can be loaded without exceeding the 2000-pound limit.

---

### Step 3: Calculate the Number of Trucks Needed

Now, we divide the total number of flagstones by the maximum number of flagstones per truck:

$$
\left\lceil \frac{80}{26} \right\rceil = \left\lceil 3.0769 \right\rceil = 4
$$

This means that **3 trucks** can carry **78 flagstones** (26 each), and the remaining **2 flagstones** will require a **4th truck**.

---

### Step 4: Consider the Real-World Constraint

Even though the **total weight (6000 pounds)** is exactly divisible by the **truck capacity (2000 pounds)**, the **flagstones are indivisible**. Therefore, we cannot split a flagstone between trucks. This constraint forces us to **round up** the number of trucks needed, even if the total weight fits perfectly.

---

### Final Conclusion

While the total weight suggests that **3 trucks** could suffice, the **indivisibility of the flagstones** and the **weight limit per truck** make it necessary to use **4 trucks** to transport all 80 flagstones without exceeding the weight limit on any truck.

$$
\boxed{4}
$$

4

## Step 1: Determine the total weight of the flagstones to be transported.
To find the total weight of the flagstones, we need to multiply the number of flagstones by the weight of each flagstone. total_weight = 80 flagstones * 75 pounds/flagstone = 6000 pounds.

## Step 2: Determine the number of trucks required to carry the flagstones in one trip.
To find the number of trucks needed, we divide the total weight of the flagstones by the weight that each truck can transport. number_of_trucks = total_weight / 2000 pounds/truck.

## Step 4: Calculate the number of trucks.
number_of_trucks = 6000 / 2000 = 3.

The final answer is: $\boxed{3}$

Each flagstone weighs 75 pounds, and the total weight of 80 flagstones is calculated as follows:  
80 × 75 = 6000 pounds.  

Each delivery truck can carry a maximum weight of 2000 pounds.  

However, due to the weight of each flagstone and the truck's capacity, not all trucks can be loaded to exactly 2000 pounds with whole flagstones, as the flagstones cannot be split.  

The maximum number of flagstones one truck can carry is determined by:  
2000 ÷ 75 = 26.666...  
Since partial flagstones are not allowed, each truck can carry at most 26 flagstones (26 × 75 = 1950 pounds), which is under the 2000-pound limit. Carrying 27 flagstones would exceed the limit (27 × 75 = 2025 pounds).  

With 26 flagstones per truck, the number of flagstones that can be transported by multiple trucks is:  
26 × 3 = 78 flagstones (using three trucks).  

This leaves 80 − 78 = 2 flagstones remaining, weighing 2 × 75 = 150 pounds.  

A fourth truck is required to carry these remaining 2 flagstones, as they must be transported in one trip.  

Although the total weight (6000 pounds) matches the combined capacity of three trucks (2000 × 3 = 6000 pounds), the indivisible nature of the flagstones means that no truck can carry exactly 2000 pounds (since 2000 ÷ 75 is not an integer), and the weight constraint per truck prevents carrying 27 flagstones. Therefore, distributing the flagstones to avoid exceeding the 2000-pound limit per truck necessitates four trucks.  

**Truck Loading Example for One Trip:**  
- Three trucks: each carrying 26 flagstones × 75 pounds = 1950 pounds.  
- One truck: carrying 2 flagstones × 75 pounds = 150 pounds.  

No other distribution is possible with three trucks without exceeding the weight limit per truck. Thus, **4 trucks** are needed to transport all 80 flagstones in one trip.

\boxed{4}

I need to find how many trucks are required to transport 80 flagstones in one trip.

Given information:
- Each flagstone weighs 75 pounds
- Each truck can carry 2000 pounds maximum
- Need to transport 80 flagstones

First, I'll calculate the total weight of all flagstones:
Total weight = 80 flagstones × 75 pounds per flagstone
Total weight = 6,000 pounds

Next, I'll determine how many trucks are needed:
Number of trucks = Total weight ÷ Weight capacity per truck
Number of trucks = 6,000 pounds ÷ 2,000 pounds per truck
Number of trucks = 3

Let me verify: 3 trucks × 2,000 pounds per truck = 6,000 pounds ✓

Therefore, 3 trucks will be needed to transport 80 flagstones in one trip.